Unsaturation (IHD) 2 hydrogen Needed
IHD = [(2n+2) -H]/2
(H: X=1, N=-1, O= zero)
Unsaturation:
Double bonds = 1
Rings = 1
Triple Bonds = 2
The degrees of unsaturation in a molecule are additive — a
molecule with one double bond has one degree of unsaturation, a molecule with
two double bonds has two degrees of unsaturation, and so forth.
If pH+ is 7
It is Neutral solution
POH=14-pH
pH=-lg[H⁺]
pOH = 14 + lg0.025 = 12.4
A., I believe. It's either an ionic, covalent, or hydrogen bond
