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horsena [70]
2 years ago
6

Pls help 10 points Plsplsplspslspslspslsspsls

Chemistry
2 answers:
Len [333]2 years ago
6 0
D is the right option

Explanation:
Jupiter has many moons...
kirill [66]2 years ago
4 0
C and D is the answer
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Burning 12.00 g of an oxoacid produces 17.95 g of carbon dioxide and 4.87 g of water. Consider that 0.25
Veseljchak [2.6K]

Answer: The molecular formula will be C_6H_6O_6

Explanation:

Mass of CO_2 = 17.95 g

Mass of H_2O= 4.87 g

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 17.95 g of carbon dioxide, =\frac{12}{44}\times 17.95=4.89g of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 4.87 g of water, =\frac{2}{18}\times 4.87=0.541g of hydrogen will be contained.

Mass of oxygen in the compound = (12.00) - (4.89+0.541) = 6.57 g

Mass of C = 4.89 g

Mass of H =  0.541 g

Mass of O = 6.57 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{4.89g}{12g/mole}=0.407moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.541g}{1g/mole}=0.541moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{6.57g}{16g/mole}=0.410moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.407}{0.407}=1

For H =\frac{0.541}{0.407}=1

For O = \frac{0.410}{0.407}=1

The ratio of C : H : O = 1: 1  : 1

Hence the empirical formula is CHO.

Hence the empirical formula is CHO

The empirical weight of CHO = 1(12)+1(1)+1(16)= 29 g.

If 0.25 moles has mass of 44.0 g

Thus 1 mole has mass of = \frac{44.0}{0.25}\times 1=176g

Thus molecular mass is 176 g

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{176g}{29g}=6

The molecular formula will be=6\times CHO=C_6H_6O_6

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3 years ago
What are the oxidation numbers of the atoms in this reaction?
ipn [44]
A, B and D should be the ones you should check
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3 years ago
What is an ideal gas? how many ideal gases are there in the universe?
tiny-mole [99]
Ideal gases are hypothetical gases whose molecules occupy negligible space and have no interactions, and that consequently obeys the gas laws exactly.
Not exactly sure about the amount...
I hope this helps! :)
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3 years ago
The formula weight of magnesium hydroxide is________ amu.<br> amu.
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58.316  is the formula weight of magnesium hydroxide

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1 year ago
How do intermolecular forces affect the shape of a drop? Check all the possible answers. A) Stronger IMFs lead to stronger adhes
amm1812

Given what we know, we can confirm that option A is correct in that Stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter.

<h3>What are IMFs?</h3>

IMF is the acronym used to describe intermolecular forces. These forces include all of the forces that bind molecules together, of which water has plenty. This bonding force creates a high adhesion and thus gives water its surface tension which makes it stay together in the shape of a drop.

Therefore, we can confirm that stronger IMFs lead to stronger adhesion, producing rounder drops with a smaller diameter, and therefore that option A is correct.

To learn more about molecular forces visit:

brainly.com/question/25863653?referrer=searchResults

5 0
2 years ago
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