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2 years ago

How many grams of 02 will be formed from 6.5 moles of KCLO3

Chemistry

2 answers:

Allisa [31]2 years ago

4 0

Answer:

312 g of O₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO₃ —> 2KCl + 3O₂

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Next, we shall determine the number of mole of O₂ produced by the reaction of 6.5 moles of KClO₃. This can be obtained as follow:

From the balanced equation above,

2 mole of KClO₃ decomposed to 3 moles of O₂.

Therefore, 6.5 moles of KClO₃ will decompose to produce = (6.5 × 3)/2 = 9.75 moles of O₂.

Finally, we shall determine the mass of 9.75 moles of O₂. This can be obtained as follow:

Mole of O₂ = 9.75 moles

Molar mass of O₂ = 2 × 16 = 32 g/mol

Mass of O₂ =?

Mole = mass / Molar mass

9.75 = Mass of O₂ / 32

Cross multiply

Mass of O₂ = 9.75 × 32

Mass of O₂ = 312 g

Thus, 312 g of O₂ were obtained from the reaction.

gayaneshka [121]2 years ago

3 0

Answer:

3.1 × 10² g

Explanation:

Step 1: Write the balanced decomposition reaction

KClO₃ ⇒ KCl + 1.5 O₂

Step 2: Calculate the moles of O₂ formed from 6.5 moles of KClO₃

The molar ratio of KClO₃ to O₂ is 1:1.5.

6.5 mol KClO₃ × 1.5 mol O₂/1 mol KClO₃ = 9.8 mol O₂

Step 3: Calculate the mass corresponding to 9.8 moles of O₂

The molar mass of O₂ is 32.00 g/mol.

9.8 mol × 32.00 g/mol = 3.1 × 10² g

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Read that From picture and tell me the answer please

Dafna11 [192]

Answer:

1g Hydrogen

Explanation:

<h3>Getting to the equation:</h3>

Calcium in water reacts vigorously to give a cloudy white Precipitate (compound) called Calcium hydroxide alongwith the evolution of Hydrogen gas.

$\boxed{ \mathsf{Ca + H_2O \rightarrow Ca(OH)_2 + H_2}}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Balancing the equation: </h3>

This reaction is not in it's balanced form! The number of atoms of Hydrogen on the left is 2 while that on the right is 4,I.e.,they're not equal.

Adding a 2 in front of H2O solves the problem by making the number of atoms of each element on both the sides equal.

$\mathsf{Ca +2 H_2O \rightarrow Ca(OH)_2 + H_2}$

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Observations:</h3>

Looking into the equation more carefully, we see:

1 atom of Calcium reacts with 2 molecules of water to give 1 molecule of Calcium Hydroxide alongwith 1 molecule of Hydrogen gas.

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Gram atomic and molecular masses </h3>

Mass of one atom of Calcium = it's gram atomic mass

= 40 g

Mass of one "molecule" of Hydrogen

= it's Gram molecular mass

= gram mass of one atom × number of atoms in one molecule

= 1 × 2

= 2 g

So,

according to our observation:

One atoms of Calcium gives one molecule of Hydrogen (during the particular reaction)

=> 40g of Calcium gives = 2g of Hydrogen

•°• 1 g of Calcium gives = $\frac{2}{40}$

= $\frac{1}{20}$ g Hydrogen

- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

<h3>Answer:</h3>

We're provided with 20g of Calcium,

=> 20g of Calcium gives = 20 × $\frac{1}{20}$ g H2

= 1 g H2

_______________

Hope this helps!

6 0

2 years ago

A dunk tank hold 30,533 moles of water? How many grams of water are in the tank?

liubo4ka [24]

The mass of water in the tank, given the data from the question is 549594 g

<h3> Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation:

Mole = mass / molar mass

<h3>How to determine the mass of water in the tank</h3>

From the question given above, the following data were obtained:

Mole of water = 30533 moles
Molar mass of water = 18 g/mol
Mass of water = ?

The mass of the water can be obtained as follow:

Mass = mole × molar mass

Mass of water = 30533 × 18

Mass of water = 549594 g

Learn more about mole:

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3 0

1 year ago

Plesse help asap!!!

Naily [24]

Answer:

4.4×10² cm³

Explanation:

From the question given above, the following data were obtained:

Diameter (d) = 68.3 mm

Height (h) = 0.120 m

Volume (V) =?

Next, we shall convert the diameter (i.e 68.3 mm) to cm.

This can be obtained as follow:

10 mm = 1 cm

Therefore

68.3 mm = 68.3 mm / 10 mm × 1 cm

68.3 mm = 6.83 cm

Therefore, the diameter 68.3 mm is equivalent 6.83 cm.

Next, we shall convert the height (i.e 0.120 m) to cm. This can be obtained as follow:

1 m = 100 cm

Therefore,

0.120 m = 0.120 m/ 1 m × 100 cm

0.120 m = 12 cm

Therefore, the height 0.120 m is equivalent 12 cm.

Next, we shall determine the radius of the cylinder. This can be obtained as follow:

Radius (r) is simply half of a diameter i.e

Radius (r) = Diameter (d) /2

r = d/2

Diameter (d) = 6.83 cm

Radius (r) =?

r = d/2

r = 6.83/2

r = 3.415 cm

Finally, we shall determine the volume of the cylinder as follow:

Radius (r) = 3.415 cm

Height (h) = 12 cm

Volume (V) =?

Pi (π) = 3.14

V = πr²h

V = 3.14 × (3.415) ² × 12

V = 440 cm³

V = 4.4×10² cm³

Therefore, the volume of the cylinder is 4.4×10² cm³

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2 years ago

Given the following list of densities, which materials would float in a molten vat of lead provided that they do not themselves

vampirchik [111]

Answer:

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Explanation:

Step 1: Given data

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Density of Glass: 2.6 g/mL

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Density of platinum: 21.4 g/mL

Step 2: Determine which material will float in molten lead

Density is an intrinsic property of matter. Less dense materials float in more dense materials. The materials whose density is lower than that of lead and will therefore float on it are glass and charcoal.

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2 years ago

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3 years ago

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