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iren2701 [21]
3 years ago
15

Is 9.561 a repeating decimal?

Mathematics
2 answers:
Valentin [98]3 years ago
7 0

Not the way you wrote it, it isn't.  Nothing you wrote is repeated, and
there's no note saying that the  561,  or the  61,  or the  1  repeats.


Dmitrij [34]3 years ago
3 0
No it is only a repeating decimal if the number is repetitive for example .3333333 is a repeating decimal because the 3 repeats with no change of pattern
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On a coordinate plane, 2 polygons are shown. Polygon A B C D has points (1, negative 6), (5, negative 6), (6, negative 2), and (
irga5000 [103]

Answer:

The correct option is;

Use a scale factor of 2

Step-by-step explanation:

The parameters given are;

A = (1, -6)

B = (5, -6)

C = (6, -2)

D = (0, -2)

A'' = (1.5, 4)

B'' = (3.5, 4)

C'' = (4, 2)

D'' = ( 1, 2)

We note that the length of side AB in polygon ABCD = √((5 -1)² + (-6 - (-6))²) = 4

The length of side A''B'' in polygon A''B''C''D'' = √((3.5 -1.5)² + (4 - 4)²) = 2

Which gives;

AB/A''B'' = 4/2 = 2

Similarly;

The length of side BC in polygon ABCD = √((6 -5)² + (-2 - (-6))²) = √17

The length of side B''C'' in polygon A''B''C''D'' = √((4 -3.5)² + (2 - 4)²) = (√17)/2

Also we have;

The length of side CD in polygon ABCD = √((6 -0)² + (-2 - (-2))²) = 6

The length of side C''D'' in polygon A''B''C''D'' = √((4 -1)² + (2 - 2)²) = 3

For the side DA  and D''A'', we have;

The length of side DA in polygon ABCD = √((1 -0)² + (-6 - (-2))²) = √17

The length of side D''A'' in polygon A''B''C''D'' = √((1.5 -1)² + (4 - 2)²) = (√17)/2

Therefore the Polygon A B C D can be obtained from polygon A''B''C''D'' by multiplying each side of polygon A''B''C''D'' by 2

The correct option is therefore;

Use a scale factor of 2.

3 0
4 years ago
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mihalych1998 [28]

Answer:

The answer would be C $25,181.70

since i kinda forgot the proper way its just 10000 times 1.08 them do that 12 times

3 0
3 years ago
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14 divided by 3 (27-11) x 3
stira [4]

14 ÷3 (27-11) x 3 = 224

4 0
4 years ago
The opposite of -17 I need the answer please and thanks
alex41 [277]
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3 years ago
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Eva bought popcorn, candy and a drink at the movies. The popcorn was three times as expensive as the candy and the drink was twi
aliina [53]

The cost of popcorn, drinks, and candy is 5.25, 3.5, and 1.75.

Given,

Eva bought popcorn, candy, and a drink at the movies.

The popcorn was three times as expensive as the candy and the drink was twice as expensive as the candy.

Eva spent a total of 10.50

We need to find the cost of popcorn, candy, and drink.

We have,

Let the cost of the candy be C.

Now,

The popcorn was three times as expensive as the candy.

Cost of the Popcorn = 3C

The drink was twice as expensive as the candy.

Cost of the drink = 2C

Eva spent a total of 10.50

Cost of popcorn + cost of drink + cost of candy = 10.50

3C + 2C + C = 10.50

Adding

6C = 10.50

Dividing by 6 into both sides

C = 10.50/6

C = 1.75.

Now,

Cost of the Popcorn = 3C = 3 x 1.75 = 5.25

Cost of the drink = 2C = 2 x 1.75 = 3.5

Cost of the candy = C = 1.75

Thus the cost of popcorn, drinks, and candy is 5.25, 3.5, and 1.75.

Learn more about finding the cost of items with the given total cost here:

brainly.com/question/357628

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