Explain how you would use ir spectroscopy to distinguish between 1-bromo-3-methyl-2-butene and 2-bromo-3-methyl-2-butene.
1 answer:
Structures of <span>1-bromo-3-methyl-2-butene and </span>2-bromo-3-methyl-2-butene are shown below.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.
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The question is incomplete, complete question is :
A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.
Answer:
The final volume of the solution will be 0.236 L.
Explanation:
Concentration of sodium carbonate solution before dilution =
Volume of sodium carbonate solution before dilution =
Concentration of sodium carbonate solution after dilution =
Volume of sodium carbonate solution after dilution =
Dilution equation is given by:
1 mL = 0.001 L
236 mL = 0.236 L
The final volume of the solution will be 0.236 L.