Explain how you would use ir spectroscopy to distinguish between 1-bromo-3-methyl-2-butene and 2-bromo-3-methyl-2-butene.
1 answer:
Structures of <span>1-bromo-3-methyl-2-butene and </span>2-bromo-3-methyl-2-butene are shown below.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.
It can be seen that <span>1-bromo-3-methyl-2-butene is containing a C-H bond in which carbon is sp</span>² hybridized (i.e. =C-H) while such bonding is absent in 2-bromo-3-methyl-2-butene.
So, as we know that the peak of C-H stretching of alkenes is found in the region of 3010-3100 cm⁻¹ with medium intensity. Therefore, 1-bromo-3-methyl-2-butene will show this peak and 2-bromo-3-methyl-2-butene will lack this peak in IR spectrum.
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<h2>Hello!</h2>
The answer is:
The empirical formula is the option B.
The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.
We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.
Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)
A.
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.
B.
It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.
C.
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.
D.
It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.
Hence, the empirical formula is the option B.
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