The same sample of gas at different temperatures shows that at low
temperatures, most molecules have speeds close to their average
speed.
<h3>
What does the Maxwell-Boltzmann distribution graph show?</h3>
Put simply, a Maxwell-Boltzmann distribution graph shows how the energy of gas particles varies within a system.
This is solely a measurement of the speeds of particles because kinetic energy is directly related to speed.
The Maxwell-Boltzmann distribution in chemistry is the subject of this article.
We will begin by describing how to read a graph of the Maxwell-Boltzmann distribution. This will involve taking a closer look at things like the typical energy and the most likely energy.
The graph will then be changed under various circumstances, such as when a catalyst is added or the temperature is raised.
The Maxwell-Boltzmann distribution, which we previously mentioned, is a probability function that depicts the distribution of energy among the particles of an ideal gas. (For more information on this topic, see Chemical Kinetics.)
To learn more about Maxwell distribution, refer
to brainly.com/question/24419453
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Answer:
b,c,d
Explanation:
gasses exert pressure, all particles of a gas sample move at the same speed. gas particles can exchange kinetic energy when they collide.
As we can see the chemical equation is balanced.K3PO4 + Al(NO3)3 → 3KNO3 + AlPO4
So, by principle of conservation of mass when 1 mole of K3PO4 reacts with 1 mol of Al(NO3)3 , it peoduces 3 mol of KNO3 and 1 mol of AlPO4
So, when 2.5 moles of potassium phosphate react and Al(NO3)3 is present in excess , 2.5*3= 7.5 mol of KNO3 is formed
Answer:
In chemical bonding: Arrangement of the elements. The horizontal rows of the periodic table are called periods. Each period corresponds to the successive occupation of the orbitals in a valence shell of the atom, with the long periods corresponding to the occupation of the orbitals of a d subshell.
Explanation:
Explanation:
Equation of the reaction:
Br2(l) + Cl2(g) --> 2BrCl(g)
The enthalpy change for this reaction will be equal to twice the standard enthalpy change of formation for bromine monochloride, BrCl.
The standard enthalpy change of formation for a compound,
ΔH°f, is the change in enthalpy when one mole of that compound is formed from its constituent elements in their standard state at a pressure of 1 atm.
This means that the standard enthalpy change of formation will correspond to the change in enthalpy associated with this reaction
1/2Br2(g) + 1/2Cl2(g) → BrCl(g)
Here, ΔH°rxn = ΔH°f
This means that the enthalpy change for this reaction will be twice the value of ΔH°f = 2 moles BrCl
Using Hess' law,
ΔH°f = total energy of reactant - total energy of product
= (1/2 * (+112) + 1/2 * (+121)) - 14.7
= 101.8 kJ/mol
ΔH°rxn = 101.8 kJ/mol.
