Answer:
Explanation:
Hello,
In this case, given the percent ionization and the concentration of the acid, one computes the concentration of hydrogen ions as follows:
![\% ionization=\frac{[H^+]}{[HA]}*100\%](https://tex.z-dn.net/?f=%5C%25%20ionization%3D%5Cfrac%7B%5BH%5E%2B%5D%7D%7B%5BHA%5D%7D%2A100%5C%25)
![[H^+]=\frac{\% ionization*[HA]}{100\%} =\frac{4\%*0.30M}{100\%}=0.012M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%5Cfrac%7B%5C%25%20ionization%2A%5BHA%5D%7D%7B100%5C%25%7D%20%3D%5Cfrac%7B4%5C%25%2A0.30M%7D%7B100%5C%25%7D%3D0.012M)
Therefore the Ka is computed by using the equilibrium expression:
![Ka=\frac{[H^+][A^-]}{[HA]} =\frac{0.012M*0.012M}{0.30M-0.012M}\\ \\Ka=5x10^{-4}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%5E%2B%5D%5BA%5E-%5D%7D%7B%5BHA%5D%7D%20%3D%5Cfrac%7B0.012M%2A0.012M%7D%7B0.30M-0.012M%7D%5C%5C%20%5C%5CKa%3D5x10%5E%7B-4%7D)
And the pH:
![pH=-log([H^+])=-log(0.012)\\\\pH=1.92](https://tex.z-dn.net/?f=pH%3D-log%28%5BH%5E%2B%5D%29%3D-log%280.012%29%5C%5C%5C%5CpH%3D1.92)
Regards.
Answer:
The answer is "33.95 
".
Explanation:
Formula:
where
Given value:
convert temperature celsius (°C) to Kelvin (K):
After solving the value it will give:
= 33.95
The independent variable would be the type of liquid the dependen is the evaporation rates
On the edges or the outer magnetic fields
