X^(3/5) = 1.84
x^(3/5) = (1.84)
Raise both sides of the equation to (5/3).
This is so that on the side with x, 3/5 * 5/3 = 1.
(x^3/5 )^5/3 = (1.84)^(5/3)
x^(3/5 * 5/3) = 1.84^(5/3)
x^1 = 1.84^(5/3)
x = 1.84^(5/3)
But remember we are solving for x^2.
x = 1.84^(5/3)
x^2 = (1.84^(5/3))^2
x^2 = 1.84^(5/3 *2 )
x^2 = 1.84^(10/3)
Use a calculator here.
x^2 = 1.84^(10/3) ≈ 7.63
Option A.
Cheers!
Answer:
The range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
Step-by-step explanation:
We are given that the lengths of pregnancies in a small rural village are normally distributed with a mean of 262 days and a standard deviation of 17 days.
Let X = <u><em>lengths of pregnancies in a small rural village</em></u>
SO, X ~ Normal(
)
Here,
= population mean = 262 days
= standard deviation = 17 days
<u>Now, the 68-95-99.7 rule states that;</u>
- 68% of the data values lies within one standard deviation points.
- 95% of the data values lies within two standard deviation points.
- 99.7% of the data values lies within three standard deviation points.
So, middle 68% of most pregnancies is represented through the range of within one standard deviation points, that is;
[
,
] = [262 - 17 , 262 + 17]
= [245 days , 279 days]
Hence, the range in which we can expect to find the middle 68% of most pregnancies is [245 days , 279 days].
21Step-by-step explanation:
Answer: 50a+2
Step-by-step explanation:
1. Simplify 5a5a\5a5a to 1.
1+5×10a+10
2.Simplify 5×10a to 50a.
1+50a+10
3.Cancel 10.
1+50a+1
4. Collect like terms.
50a+(1+1)
5. Simplify.
50a+2
Answer:
6 cartons
Step-by-step explanation:
4 is 40% of 10
so you need to find 40% of 15
15*.4=6
.4 is equal to 40%