we will proceed to resolve each case to determine the solution
we have


we know that
If an ordered pair is the solution of the inequality, then it must satisfy the inequality.
<u>case a)</u> 
Substitute the value of x and y in the inequality

-------> is true
so
The ordered pair
is a solution
<u>case b)</u> 
Substitute the value of x and y in the inequality

-------> is False
so
The ordered pair
is not a solution
<u>case c)</u> 
Substitute the value of x and y in the inequality

-------> is False
so
The ordered pair
is not a solution
<u>case d)</u> 
Substitute the value of x and y in the inequality

-------> is True
so
The ordered pair
is a solution
<u>case e)</u> 
Substitute the value of x and y in the inequality

-------> is False
so
The ordered pair
is not a solution
Verify
using a graphing tool
see the attached figure
the solution is the shaded area below the line
The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality
Answer:
Line segments are congruent if they have the same length. However, they need not be parallel. They can be at any angle or orientation on the plane. In the figure above, there are two congruent line segments. If you drag any of the four endpoints, the other segment will change length to remain congruent with the one you are changing.
Factor the Polynomial by solving x^2 + bx + c = 0.
m^2 - mv - 56v^2
Factor by grouping.
(m−8v)(m+7v).
x^2 + bx + c = 0
