Ask question

Ask question

All categories

Dennis_Churaev [7]

2 years ago

8

Car A travels 170 miles in 4 hours. Car B travels 306 miles in 4 hours. Car B travels 306 miles in 4 hours. Which car has the fa

stest average speed?

1 answer:

sukhopar [10]2 years ago

7 0

Answer:

car b

Step-by-step explanation:

car a = 170/4=42.5 mph

car b = 306/4=76.5 mph

You might be interested in

Help I need the answers

jolli1 [7]

240
/ \
5 48
/ \
6 8
/ \ / \
3 2 4 2

7 0

3 years ago

Read 2 more answers

2+2 pls help btw 4 .....

Vsevolod [243]

Answer:

is it 22.

Step-by-step explanation:

is it?

5 0

3 years ago

Read 2 more answers

Match the fractions that are equivalent to each other?

MrRissso [65]

Answer:

1&a 2&b 3&c 4&d

Step-by-step explanation:

...

4 0

3 years ago

Read 2 more answers

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

4 0

3 years ago

Cual es la energía cinética de un cuerpo de 20kg que viaja a una velocidad de 1 m/s ?

Hitman42 [59]

Answer:

hola como estas amigo de unde stii ca

8 0

2 years ago