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Olin [163]
3 years ago
9

(3x-5)(2x+7) Please show all the work Thank You

Mathematics
1 answer:
dalvyx [7]3 years ago
8 0

(3x-5)(2x+7) =

= 3x·2x + 3x·7 - 5·2x - 5·7

= 6x² + 21x - 10x - 35

= 6x² + 11x - 35

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What is the greatest common factor for 84 and 56?
anzhelika [568]

Factors of 56 are: 1, 2, 4, 7, 8, 14, 28, 56

<span>Factors of 84 are: 1, 2, 3, 4, 6, 7, 12, 14, 21, </span>28, 42, 84

The outside term multiplies by the outside term on the oposite side to equal the answer. 

Example:
Look at the factors of 84
84X1=84
2X42=84
3X28=84 
and so on!

6 0
3 years ago
What is the ratio of 225 of 15
Luden [163]

Answer:

15:1

Step-by-step explanation:

225:15

÷15 both sides

15:1

3 0
3 years ago
A pair of shoes cost $120 but they are 25% Off;
Sever21 [200]

Answer:

Discount = $30, Final price = $90

Step-by-step explanation:

25% is one quarter. 120/4=30

One quarter of 120 is 30, so - 30 would give discounted price of $90.

Similarly you could think of it like the discounted price is 75% of the original one and do 120x0.75=90 to find 75% of 120.

Hope this helped!

3 0
3 years ago
Save Work out the size of angle AED.<br> b) Work out x
Mamont248 [21]

Answer:

x = 10°

Step-by-step explanation:

a). Since, opposite angles of a cyclic quadrilateral are supplementary angles"

   Therefore, in cyclic quadrilateral ABDE,

   m∠ABD + m∠AED = 180°

   110° + m∠AED = 180°

   m∠AED = 180° - 110°

                 = 70°

b). AD = ED [Given]

   m∠EAD = m∠AED [Since, opposite angles of equal sides are equal in measure]

   m∠EAD = m∠AED = 70°

   By triangle sum theorem in ΔABD,

   m∠BAD + m∠ABD + m∠ADB = 180°

   m∠BAD + 110° + 40° = 180°

   m∠BAD = 180 - 150

                 = 30°

    m∠AEB = m∠AED + m∠DAB [By angles addition postulate]

    m∠AEB = 70° + 30°          

                  = 100°

    By triangle sum theorem in the large triangle,

    x° + m∠AEB + m∠EAB = 180°

    x° + 100° + 70° = 180°

    x = 180 - 170

    x = 10°

8 0
2 years ago
The dual bar chart shows the hair colour of boys and girls in a year group. What fraction of the students are girls? Give your a
Tems11 [23]

Answer:

5/11

Step-by-step explanation:

Black= 22 b+17 g

Brown= 4 b +18 g

Blonde= 25 b+ 10 g

Red= 21 b+ 15 g

Total number= 22+17+4+18+25+10+21+15= 132

Number of girls= 17+18+10+15= 60

Girls are 60/132= 2 × 2 × 3 × 5/ 2 × 2 × 3 × 11= 5/11 of all students

7 0
3 years ago
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