Answer:
Mass = 0.00541 g
Explanation:
We will convert the larger given values in to smaller by rounding these figures.
Given data:
Mass of zinc sulfide = 43 g
Mass of oxygen = 44.2 g
Mass of zinc oxide = ?
Solution:
Chemical equation:
2ZnS + 3O₂ → 2ZnO + 3SO₂
Number of moles of ZnS:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 43 g/ 97.5 g/mol
Number of moles = 0.44 mol
Number of moles of Oxygen:
<em>Number of moles = mass/ molar mass </em>
Number of moles = 44.2 g/ 32 g/mol
Number of moles = 1.4 mol
Now we will compare the moles of oxygen and zinc sulfide with zinc oxide.
ZnS : ZnO
2 : 2
0.44 : 0.44
O₂ : ZnO
3 : 2
1.4 : 2/3×1.4 =0.93
The number of moles of zinc oxide produced by ZnS are less so it will limiting reactant.
Mass of zinc oxide:
Mass = number of moles / molar mass
Mass = 0.44 mol / 81.38 g/mol
Mass = 0.00541 g
Answer:
is this have picture so I can solve
The compound that is most likely to be ionic is BaCl2
Ionic compounds are compounds made up of ions. These ions are atoms that gain or lose electrons, giving them a net positive or negative charge. Metals tend to lose electrons, thus they become cations and have a net positive charge. Non metals tend to gain electrons, forming anions that have a net negative charge.
Ten kilometers is e answer
Answer:
Percent ionic character of HI bond is 4.91%.
Explanation:
<h3>
Given Data:</h3>
Measured Dipole = 0.380D
bond distance = d = 161pm = 1.61*10^-8 cm
<h3>
Calculation:</h3>
% ionic character is determined by following equation:
% ionic= (dipole measured/dipole calculated)*100
Now,
(In above step 3*10^8 is multiplied to convert coulomb into esu)
As,
So,
Now we can % ionic character using above equation:
%ionic=(0.380D/7.728D)*100
% ionic character=4.91%
