3 years ago

What’s that formula for the area of a rhombus

Mathematics

1 answer:

sergejj [24]3 years ago

8 0

Answer:

A= pq/2

Step-by-step explanation:

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What is the area of the figure below

jek_recluse [69]

Answer:

Option A

Step-by-step explanation:

Area of the composite figure = Area of ΔABH + Area of BCGH + Area of ΔDEF

Area of ΔABH = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(6)(8-5)$

= 9 in²

Area of the trapezoid = $\frac{1}{2}(CG+BH)(\text{Distance between these lines})$

= $\frac{1}{2}(6+4)(5)$

= 25 in²

Area of ΔDEF = $\frac{1}{2}(8)(6)$

= 24 in²

Therefore, area of the given figure = 9 + 25 + 24

= 58 in²

Option A will be the correct option.

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Step-by-step explanation:

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Step-by-step explanation:

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