Y=5•(0) Which graph represents the function ?

Mathematics

1 answer:

Juli2301 [7.4K]4 years ago

4 0

Answer:
The graph that represents the function should look like the image I attached. To graph the function simply multiply five by zero to find the value of y. Once you see that the value of y is zero graph the y-intercept at (0, 0). Finally, you draw a horizontal line from the y-intercept.

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Lf x+1/x=12 then find the value of x3+1/x3

Tresset [83]

Answer:

Explanation:

First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11

Plug x value in x^3 + 1/x^3

(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332

Therefore, x^3 + 1/x^3 = 1332

4 0

3 years ago

Find an equation of the circle and sketch it if it has: Center on y=4, tangent x-axis at (–2, 0)

Digiron [165]

Answer:

$(x+2)^2+(y-4)^2=16$

OK, lets start by drawing a basic graph (the first one) so we can visualize.

We already know that the y coordinate of the circle's center is $4$ .

We know that the circle is tangent to the $X$ axis at $(-2,0)$

That means the x coordinate of the center has to be $-2$ , as the tangent is a point on the edge of the circle that touches a line at exactly one point.

The radius is the distance from the center of the circle to its edge. We know the center's location now, it is $(-2, 4)$ and a point on the edge of the circle (the tangent point) which is $(-2,0)$ . so the distance between the points is 4 which is the radius (you can use the distance formula, but it's quite oblivious.)

We can imagine the circle should look like this (the second one):

Now we can piece together an equation

The equation of a circle is $(x-h)^2+(y-k)^2=r^2$ where $(h,k)$ is the center and $r$ is the radius. When we put the numbers in: we get $(x-(-2))^2+(y-(4))^2=4^2$ which can be simplified into $(x+2)^2+(y-4)^2=16$ which is the answer.