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3 years ago

Screenshot of question attached

Mathematics

1 answer:

Liono4ka [1.6K]3 years ago

3 0

Should be the 2nd and 3rd one

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2. What equation does the model below<br> represent?<br> -<br> -

Novay_Z [31]

Answer:

minus

Step-by-step explanation:

it means minus maybe think that what it means

6 0

2 years ago

Read 2 more answers

HELP PLEASEEE

jeka94

The exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate circumference of the circle is $7.33 k m$

Explanation:

The diameter of the circle is $2 \frac{1}{3} \mathrm{km}$

Now, we shall find the circumference of the circle.

The formula to determine the circumference of the circle is given by

$C=\pi d$

Where C is the circumference , $\pi$ is 3.14 and $d=2 \frac{1}{3} \mathrm$ is the diameter of the circle.

The exact circumference of the circle is given by

$\begin{aligned}C &=\pi d \\&=(3.14)\left(2 \frac{1}{3}\right) \\&=(3.14)\left(\frac{7}{3}\right) \\&=\frac{21.98}{3}\end{aligned}$

Multiply both numerator and denominator by 100, we get,

$C=\frac{2198}{300} \\C=\frac{1099}{150}$

Converting $\frac{1099}{150}$ into mixed fraction, we get,

$C=7 \frac{49}{150}$

Thus, the exact circumference of the circle is $7 \frac{49}{150} k m$

The approximate value of the circumference can be determined by dividing the value $\frac{1099}{150}$

$C=\frac{1099}{150}=7.327$

$C=7.33km$

Thus, the approximate circumference of the circle is $7.33 k m$

3 0

3 years ago

What is the answer to 0=- 1/4(16)+b

Setler79 [48]

Answer:

Step-by-step explanation:

$0=-\dfrac{1}{4\!\!\!\!\diagup_1}\cdot16\!\!\!\!\!\diagup^4+b\\\\0=-4+b\qquad\text{add 4 to both sides}\\\\4=-4+4+b\\\\4=b\to b=4$

5 0

2 years ago

Which values are solutions to the inequality below? Check all that apply <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%7D%20"

MaRussiya [10]

X > 169 is your Answer thus: b:/d & f:

5 0

2 years ago

This hanger is in balance. There are two labels weight. What is the weight of each circle on grams?

Citrus2011 [14]

Answer:

since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight

Step-by-step explanation:

hope this helped!

6 0

2 years ago