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Lynna [10]
3 years ago
13

How do problems with extraneous solutions differ from problems with no real solutions or no solution at all? How are they simila

r?
Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0

Answer:

No real solution implies that there could possibly be imaginary solutions.

Step-by-step explanation:  Extraneous solutions are created be using certain methods to solve the problem. They are not, never were, or never will be solutions. They are created by the process that is used to solve. hope this helps you :)

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DO,h = (7,9) —> (14,18) the scale factor is ____.
notka56 [123]

Answer:

option B

2

Step-by-step explanation:

Given in the question

DO,h(7, 9) → (14, 18)

Formula to use

<h3>√(x1-x2)²+(y1-y2)²</h3>

distance formula = √((7-0)²+(9-0)²) = √(7²+9²) = √130

distance formula = √((14-0)²+(18-0)²) = √(14²+18²) = 2√130

Scale factor

√130 = 2√130

d = 2d

3 0
3 years ago
HELP VERY MUCH NEEDED PLEASE AND THANKYOUUU!!Drag the tiles to the correct locations on the image. Not all tiles will be used.
WITCHER [35]

Answer:

The perimeter of the square is 16 √ 5

The area of the square is 8√5

Step-by-step explanation:

To solve this you first need to solve 4√5 which is 8.94. This made the perimeter 35.76 which is equaled to 16√5. The area is 17.88 which is the same as 8√5.

8 0
2 years ago
Solve 2x-4÷ 5 = 4<br>really need help fast​
MrRa [10]

Answer:

x=12

Step-by-step explanation:

2x-4=20

2x=24

x=12

4 0
3 years ago
Read 2 more answers
A fair die is rolled in a board game to determine how many spaces a player can move on their turn. It has one of the numbers 1,2
Jet001 [13]

Answer:

(a)6 (b)3 (c)0.5

Step-by-step explanation:

Given a fair die with the numbers 1,2,3,4,5, or 6 on each of its faces.

  • Event A is the event of rolling an even number
  • Event B is the event of rolling an odd number.

(a)The sample space for the outcomes in this experiment is {1,2,3,4,5,6}

There are <u>6</u><u> </u>outcomes in the sample space.

n(S)=6

(b)

Event A is the event of rolling an even number

Sample space of A = {2,4,6}

There are <u>3</u> outcomes in event A.

n(A)=3

(c)The probability of event A

P(A)=\dfrac{n(A)}{n(S)} =\dfrac{3}{6} =0.5

P(A) =<u>0.5</u> is the probability that you choose an even number.

6 0
2 years ago
PLEASE ANSWER THIS FAST!!!!!!
o-na [289]

Answer:

B

Step-by-step explanation:

The correct answer is B

GK = 5 and KF = 5

5/5 = 1

HJ = 3

JG = 3

HJ/JG = 1

7 0
3 years ago
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