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damaskus [11]
3 years ago
11

Matthew records the temperature outside for one day. From 10:00 a.m. to 12:00 p.m., the temperature rises 4°C. From 12:00 p.m. t

o 2:00 p.m., it rises another 3°C. From 2:00 p.m. to 4:00 p.m., it drops 2°C. Which of the following predictions about how the temperature will change between 4:00 p.m. and 6:00 p.m. is most reasonable?
Group of answer choices

The temperature will drop 4°C.

The temperature will stay the same

The temperature will rise 3°C.

The temperature will drop 14°C.
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:will drop 4°c

Explanation:

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Answer:

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(b) To the right;

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Explanation:

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Substituting the given variables:

\Delta G^o = -8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln (5.6\cdot 10^8) = -49932 J/mol = -49.9 kJ/mol

(b) Notice that this reaction is spontaneous, since \Delta G^o < 0. This means reaction spontaneously proceeds to the right side. Besides, K > 1, this means products dominate over reactants, so reaction proceeds to the right.

(c) Given the expression of the formation constant, we can use the same expression to calculate the reaction quotient at non-standard conditions:

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Now, notice that Q_f > K_f. In this case, we have an excess of the products, this means reaction will shift to the let left to restore the equilibrium.

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\Delta G = \Delta G^o + RT ln Q_f = -49932 J/mol + 8.314 \frac{J}{K mol}\cdot 298.15 K\cdot ln(6.4\cdot 10^{14}) = 34577 J = 34.6 kJ/mol

5 0
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How do the prefixes of the –saccharide words relate to the structure of the sugar?
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Answer:

The prefixes tell you how many of each there are.

Explanation:

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Here is a table:

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di-2           hepta- 7

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