All categories

3 years ago

1) Chemical analysis of a gaseous compound show its composition to be 36.4% carbon, 57.5% fluorine, and 6.1%

Chemistry

1 answer:

Serga [27]3 years ago

5 0

Answer:

1. Empirical formula = CFH₂

Molecular formula = C₉F₉H₁₈

2. Empirical formula is CH₂Cl

Molecular formula = C₂H₄Cl₂

3. Empirical formula = CFH₂

Molecular formula = C₉F₉H₁₈

Explanation:

1) Given data

Percentage of carbon= 36.4%

Percentage of fluorine = 57.5%

Percentage of hydrogen = 6.1%

mass = 296 g

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of C = 36.4/12 = 3.03

Number of gram atoms of F = 57.5/19 = 3.03

Number of gram atoms of H = 6.1/ 1 = 6.1

Atomic ratio:

C : F : H

3.03/3.03 : 3.03/3.03 : 6.1/3.03

1 : 1 : 2

C : F : H = 1 : 1 : 2

Empirical formula is CFH₂

Now we calculate Molecular formula

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 296 / 32

n = 9.25 we take it as 9

<em> Molecular formula = n (empirical formula)</em>

Molecular formula = 9 ( CFH₂)

Molecular formula = C₉F₉H₁₈

Check the answer by calculating the molecular mass, it should be almost 296 g.

Molecular formula = C₉F₉H₁₈

molecular mass = 12 (9) + 18.998 (9) + 1 (18)

molecular mass = 108 + 170.98 + 18

molecular mass = 296.98 g/mol

2) Given data

Percentage of carbon= 24.3%

Percentage of hydrogen = 4.1%

Percentage of chlorine = 71.6%

molecular mass = 99.8 g/mol

Molecular formula = ?

Solution:

Number of gram atoms of C = 24.3/12 = 2

Number of gram atoms of H = 4.1/1 = 4.1

Number of gram atoms of Cl = 71.6/35.5 = 2

Atomic ratio:

C : H : Cl

2/2 : 4/2 : 2/2

1 : 2 : 1

C : H : Cl = 1 : 2 : 1

Empirical formula is CH₂Cl

Now we calculate Molecular formula

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 99.8 / 49.5

n = 2.02 we take it as 2

<em> Molecular formula = n (empirical formula)</em>

Molecular formula = 2 ( CH₂Cl)

Molecular formula = C₂H₄Cl₂

Check the answer by calculating the molecular mass, it should be almost 99.8 g.

Molecular formula = C₂H₄Cl₂

molecular mass = 12 (2) + 1 (4) + 2 (35.5)

molecular mass = 24 + 4 + 71

molecular mass = 99 g/mol

3) Given data

Percentage of carbon= 36.4%

Percentage of fluorine = 57.5%

Percentage of hydrogen = 6.1%

mass = 296 g

Empirical formula = ?

Molecular formula = ?

Solution:

Number of gram atoms of C = 36.4/12 = 3.03

Number of gram atoms of F = 57.5/19 = 3.03

Number of gram atoms of H = 6.1/ 1 = 6.1

Atomic ratio:

C : F : H

3.03/3.03 : 3.03/3.03 : 6.1/3.03

1 : 1 : 2

C : F : H = 1 : 1 : 2

Empirical formula is CFH₂

Now we calculate Molecular formula

Molecular formula = n (empirical formula)

n = molar mass of compound / empirical formula mass

n = 296 / 32

n = 9.25 we take it as 9

<em> Molecular formula = n (empirical formula)</em>

Molecular formula = 9 ( CFH₂)

Molecular formula = C₉F₉H₁₈

Check the answer by calculating the molecular mass, it should be almost 296 g.

Molecular formula = C₉F₉H₁₈

molecular mass = 12 (9) + 18.998 (9) + 1 (18)

molecular mass = 108 + 170.98 + 18

molecular mass = 296.98 g/mol

You might be interested in

Paul determines that the hydrogen ion concentration of his unknown solution is 3.60×10^-5 M. what is the pH of this solution?

vivado [14]

Answer:

Explanation:

The pH of a substance can be found by using the formula

$p H = - log[ H^{ + } ]$

where [ H+ ] is the hydrogen ion concentration of the solution

From the question

[ H + ] = 3.60 × 10^-5 M

So the pH is

$pH = - log(3.60 \times {10}^{ - 5} ) \\ =4.44369749923$

We have the final answer as

Hope this helps you

4 0

3 years ago

How many grams of CaCl2 are in .48 moles?

Ilia_Sergeevich [38]

Answer:

110.984 grams

Explanation:

5 0

3 years ago

If ba+2 will reacts with n-3, the formula of the compound formed is:

Ivanshal [37]

If $Ba^{+2}$ will reacts with $N^{-3}$ , the formula of the compound formed is $Ba_3N_2$ .

<h3>What is an ionic compound?</h3>

Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

Barium is a metal element and Nitrogen is a non-metal element, so they form an ionic compound. To make the formula of an ionic compound, first, we need to see the valence of the atoms, that is, how many electrons it can donate or it has to gain to have 8 electrons in the valence layer (octet rule).

Barium is in family 2, so it has two electrons in its valence layer, so it must donate these two electrons; Nitrogen is in family 15, so it has 5 electrons ins its valence layer and must gain 3 electrons.

Writing the ions they must form:

$Ba^{+2}N^{-3}$

First came the cation (positive charge), then the anion (negative charge), and the charges must change between them, without the signal, and will inform how many atoms are necessary for which element:

$Ba_3N_2$

Hence, If $Ba^{+2}$ will reacts with $N^{-3}$ , the formula of the compound formed is $Ba_3N_2$ .

Learn more about the ionic compound here:

brainly.com/question/9167977

#SPJ1

6 0

2 years ago

Can yall assist me with this lab? It is really screwing me up... No spam!! the only part that I need is the last page. I will ma

Nadusha1986 [10]

Answer:

You can block me I don't care ;-; Ive actually been wanting to be blocked because I don't want my account on brainly anymore but they cant understand that I used my school email for this account and my school email doesnt reseave emails not from the school and I cant change the email to a different one so I cant reset my password so I cant delete my account..

Explanation:

6 0

3 years ago

What is the shape pf a molecule with a triple bond

makkiz [27]

Explanation:

A molecule with a triple bond will have a linear geometry as the angles between the bonds will be 180 degrees. Hence, it will be a linear geometry.

For example, a molecule of dinitrogen ( $N_{2}$ ) has nitrogen atoms bonded through triple bond as follows.

:N ≡ N:

Since valency of nitrogen is 5 therefore, each nitrogen will have one lone pair of electrons.

8 0

3 years ago