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3 years ago

Can water boil at 0°?

Physics

1 answer:

neonofarm [45]3 years ago

3 0

Yes it can, if the air pressure is low enough.

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A physics student looks into a microscope and observes that small particles suspended in water are moving about in an irregular

Dominik [7]

Answer:

d. the actual motion is regular, but the speeds of particles are too large to observe the regular motion

Explanation:

The speeds of the particles are very large and comparatively the average free path is very small . Therefore time taken in covering the free path ( path between two consecutive collision with medium particles ) is very small . Hence the st line path covered by particles between two collision is less likely to be visible. Hence motion appears irregular or zig-zag.

6 0

3 years ago

PLEASE PLEASE HELP ME!

Vlad1618 [11]

B: heat is transferred as thermal energy by the interaction of moving particles

6 0

2 years ago

The half of the moon facing the sun is always lit, but the different phases happen

Marizza181 [45]

Answer:

the answer is the spinning of the moon lets us see different amounts of light

Explanation:

you wanna know why uh yes ok lets cut to the magic so when the moon.

3 0

2 years ago

When an object of weight w is suspended from the center of a massless string?

igomit [66]

I attached a picture of the diagram associated with this question.

Now,
When we check the vertical components of the tension in the rope, we will find that we have two equal components acting upwards.
These two components support the weight and each of them has a value of TcosΘ

The net force acting on the body is zero.
Fnet=Force of tension acting upwards-Force due to weight acting downwards
0 = 2TcosΘ -W
W = 2TcosΘ
T = W / 2cosΘ

4 0

3 years ago

Read 2 more answers

You are designing a flywheel. It is to start from rest and then rotate with a constant angular acceleration of 0.200 rev/s^2. Th

Rama09 [41]

Answer:

I = 8.75 kg m

Explanation:

This is a rotational movement exercise, let's start with kinetic energy

K = ½ I w²

They tell us that K = 330 J, let's find the angular velocity with kinematics

w² = w₀² + 2 α θ

as part of rest w₀ = 0

w = √ 2α θ

let's reduce the revolutions to the SI system

θ = 30.0 rev (2π rad / 1 rev) = 60π rad

let's calculate the angular velocity

w = √(2 0.200 60π)

w = 8.683 rad / s

we clear from the first equation

I = 2K / w²

let's calculate

I = 2 330 / 8,683²

I = 8.75 kg m

4 0

2 years ago