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Travka [436]
3 years ago
6

Toe boards shall be capable of withstanding, without failure, a force of at least _______ applied in any downward or outward dir

ection at any point along the toeboard.
Physics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

50 pounds

Explanation:

A toe board is a 2 inch x 4 inch safety wooden board used when adding roofing to a house. According to my research on the limits for toe boards, I can say that a toe board can withstand a force of at least 50 pounds applied in any downward or outward direction at any point without failure. This has been tested extensively by professionals before sale.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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Hello!
Montano1993 [528]

It is true that the  light is 15.000 more dangerous than the radiation of a microwave.

<h3>What is the wavelength?</h3>

The wavelength shows the extent or how far the wave travels. Now we know that the energy of the wave can be use to find out how much dangerous the wave is.

Now;

1.6 * 10^-19 J = 1eV

x J = 1.8 eV

x = 1.8 eV * 1.6 * 10^-19 J /1eV

x = 2.88 * 10^-19 J

Now if the energy of the microwaves is 1.2 x 10^-4 J, then it follows that;

2.88 * 10^-19 J/ 1.2 x 10^-4 J,

= 2.4 * 10^15

Hence, it is true that the  light is 15.000 more dangerous than the radiation of a microwave.

Learn more about microwave:brainly.com/question/15708046

#SPJ1

5 0
2 years ago
a condenser of capacitor 50 micro coulomb is charged to 10 volt the energy stored is can you do derivation please
Sedbober [7]

Answer:

2.5x10^-3 J

Explanation:

C=50mC

V=10V

U=1/2 C (V)^2

=1/2(50)(10)^2 x (10)^-6

=25(100)/1000000

=2.5x10^-3

8 0
3 years ago
How was the earliest version of the periodic table organized before Mendeleev?
astraxan [27]
This is how the periodic table is organized.

Hope this helps!

7 0
3 years ago
Consider a uniformly charged sphere of radius Rand total charge Q. The electric field Eout outsidethe sphere (r≥R) is simply tha
AlexFokin [52]

1) Electric potential inside the sphere: \frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})

2) Ratio Vcenter/Vsurface: 3/2

3) Find graph in attachment

Explanation:

1)

The electric field inside the sphere is given by

E=\frac{1}{4\pi \epsilon_0}\frac{Qr}{R^3}

where

\epsilon_0=8.85\cdot 10^{-12}F/m is the vacuum permittivity

Q is the charge on the sphere

R is the radius of the sphere

r is the distance from the centre at which we compute the field

For a radial field,

E(r)=-\frac{dV(r)}{dr}

Therefore, we can find the potential at distance r by integrating the expression for the electric field. Calculating the difference between the potential at r and the potential at R,

V(R)-V(r)=-\int\limits^R_r  E(r)dr=-\frac{Q}{4\pi \epsilon_0 R^3}\int r dr = \frac{-Q}{8\pi \epsilon_0 R^3}(R^2-r^2)

The potential at the surface, V(R), is that of a point charge, so

V(R)=\frac{Q}{4\pi \epsilon_0 R}

Therefore we can find the potential inside the sphere, V(r):

V(r)=V(R)+\Delta V=\frac{Q}{4\pi \epsilon_0 R}+\frac{-Q}{8\pi \epsilon_0 R^3}(R^2-r^2)=\frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})

2)

At the center,

r = 0

Therefore the potential at the center of the sphere is:

V(r)=\frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})\\V(0)=\frac{3Q}{8\pi \epsilon_0 R}

On the other hand, the potential at the surface is

V(R)=\frac{Q}{4\pi \epsilon_0 R}

Therefore, the ratio V(center)/V(surface) is:

\frac{V(0)}{V(R)}=\frac{\frac{3Q}{8\pi \epsilon_0 R}}{\frac{Q}{4\pi \epsilon_0 R}}=\frac{3}{2}

3)

The graph of V versus r can be found in attachment.

We observe the following:

- At r = 0, the value of the potential is \frac{3}{2}V(R), as found in part b) (where V(R)=\frac{Q}{4\pi \epsilon_0 R})

- Between r and R, the potential decreases as -\frac{r^2}{R^2}

- Then at r = R, the potential is V(R)

- Between r = R and r = 3R, the potential decreases as \frac{1}{R}, therefore when the distance is tripled (r=3R), the potential as decreased to 1/3 (\frac{1}{3}V(R))

Learn more about electric fields and potential:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0
3 years ago
When you apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed ().When you apply a f
elena-s [515]

Answer:

Explanation:

When we apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed. So net force on the block is zero .

It implies that a force ( frictional ) acts on it which is equal to 76 N in opposite direction ( friction )

When we apply  a greater force on it it starts moving with acceleration .

This time kinetic friction acts on it due to rough ground equal to 76 N .This is limiting friction ( maximum friction )

Net force on the body in later case

= 89 - 76

= 13 N

Force by ground on the block in horizontal direction = 76 N ( FRICTIONAL FORCE )

=

3 0
3 years ago
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