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Vanyuwa [196]
3 years ago
13

What is mechanical energy​

Physics
2 answers:
inessss [21]3 years ago
8 0

Answer:

Mechanical energy is the sum of kinetic and potential energy in an object that is used to do work.

Explanation:

i hope this helps u

netineya [11]3 years ago
3 0

Explanation:  

In physical sciences, mechanical energy is the sum of potential energy and kinetic energy. It is the macroscopic energy associated with a system. The principle of conservation of mechanical energy states that if an isolated system is subject only to conservative forces, then the mechanical energy is constant. If an object moves in the opposite direction of a conservative net force, the potential energy will increase; and if the speed (not the velocity) of the object changes, the kinetic energy of the object also changes. In all real systems, however, nonconservative forces, such as frictional forces, will be present, but if they are of negligible magnitude, the mechanical energy changes little and its conservation is a useful approximation. In elastic collisions, the kinetic energy is conserved, but in inelastic collisions some mechanical energy may be converted into thermal energy. The equivalence between lost mechanical energy (dissipation) and an increase in temperature was discovered by James Prescott Joule.

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Why is soil considered a non-renewable resource?
Sever21 [200]

Answer:D

Explanation: It is considered non renewable, it takes hundreds of years to renovate and because our life span as humans is very limited we don’t get to see how it regenerates.

7 0
2 years ago
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What are the factor that affect gravity​
valentinak56 [21]

Explanation:

The factors that affect gravity are as follows:

1. mass of body

2. acceleration

<em>Keep</em><em> </em><em>smiling </em><em>and</em><em> </em><em>hope</em><em> </em><em>u</em><em> </em><em>are</em><em> </em><em>satisfied</em><em> </em><em>with</em><em> </em><em>my</em><em> </em><em>answer</em><em>.</em><em>Have</em><em> </em><em>a</em><em> </em><em>good</em><em> </em><em>day</em><em> </em><em>:</em><em>)</em>

6 0
3 years ago
two astronauts are taking a spacewalk outside the International Space Station the first astronaut has a mass of 64 kg the second
Fittoniya [83]

Answer:

Approximately 0.88\; {\rm m \cdot s^{-1}} to the right (assuming that both astronauts were originally stationary.)

Explanation:

If an object of mass m is moving at a velocity of v, the momentum p of that object would be p = m\, v.

Since momentum of this system (of the astronauts) conserved:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\end{aligned}.

Assuming that both astronauts were originally stationary. The total initial momentum of the two astronauts would be 0 since the velocity of both astronauts was 0\!.

Therefore:

\begin{aligned} &(\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

The final momentum of the first astronaut (m = 64\; {\rm kg}, v = 0.8\; {\rm m\cdot s^{-1}} to the left) would be p_{1} = m\, v = 64\; {\rm kg} \times 0.8\; {\rm m\cdot s^{-1}} = 51.2\; {\rm kg \cdot m \cdot s^{-1}} to the left.

Let p_{2} denote the momentum of the astronaut in question. The total final momentum of the two astronauts, combined, would be (p_{1} + p_{2}).

\begin{aligned} & p_{1} + p_{2} \\ &= (\text{Total Final Momentum}) \\ &= (\text{Total Initial Momentum})\\ &= 0\end{aligned}.

Hence, p_{2} = (-p_{1}). In other words, the final momentum of the astronaut in question is the opposite of that of the first astronaut. Since momentum is a vector quantity, the momentum of the two astronauts magnitude (51.2\; {\rm kg \cdot m \cdot s^{-1}}) but opposite in direction (to the right versus to the left.)

Rearrange the equation p = m\, v to obtain an expression for velocity in terms of momentum and mass: v = (p / m).

\begin{aligned}v &= \frac{p}{m} \\ &= \frac{51.2\; {\rm kg \cdot m \cdot s^{-1}}}{64\; {\rm kg}} && \genfrac{}{}{0}{}{(\text{to the right})}{} \\ &\approx 0.88\; {\rm m\cdot s^{-1}} && (\text{to the right})\end{aligned}.

Hence, the velocity of the astronaut in question (m = 58.2\; {\rm kg}) would be 0.88\; {\rm m \cdot s^{-1}} to the right.

5 0
2 years ago
Answer the following question about the attached diagram:
Paladinen [302]
I'm not entirely sure, but I think the first is A, and the second is inverted.
3 0
3 years ago
Read 2 more answers
During typical urination, a man releases about 400 mL of urine in about 30 seconds through the urethra, which we can model as a
gregori [183]

Answer:

Explanation:

Given:

volume of urine discharged, V=400~mL=0.4~L=4\times 10^{-4}~m^3

time taken for the discharge, t=30~s

diameter of cylindrical urethra, d=4\times10^{-3}~m

length of cylindrical urethra, l=0.2~m

density of urine, \rho=1000~kg/m^3

a)

we have volume flow rate Q:

Q=A.v & Q=\frac{V}{t}

where:

A= cross-sectional area of urethra

v= velocity of flow

A.v=\frac{V}{t}

\frac{\pi d^2}{4}\times v=\frac{4\times 10^{-4}}{30}

v=\frac{4\times4\times 10^{-4}}{30\times \pi (4\times 10^{-3})^2}

v=1.06~m/s

b)

The pressure required when the fluid is released at the same height as the bladder and that the fluid is at rest in the bladder:

P=\rho.g.l

P=1000\times 9.8\times 0.2

P=1960~Pa

5 0
3 years ago
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