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kaheart [24]
2 years ago
13

What Element is represented by the diagram?

Physics
2 answers:
pychu [463]2 years ago
8 0

Answer:Beryllium

Explanation:

mash [69]2 years ago
8 0

good question Explanation:

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Objects in free fall are weightless. true or false???
frez [133]

The answer is false

7 0
3 years ago
200 pages about string thirory
joja [24]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
Which of the following cars have the most kinetic energy
faltersainse [42]
<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>

\huge\boxed{OptionA}

<h2>_____________________________________</h2><h2>DATA:</h2><h3>Blue Car: </h3>

mass = 4 kg

velocity = 5 m/s^2

<h3 /><h3>Orange truck:</h3>

Mass= 2kg

Velocity = 7m/s^2

<h3 /><h3>Grey Car:</h3>

mass = 6 kg

velocity = 4m/s^2

<h3 /><h3>Green Car:</h3>

Mass = 8 kg

Velocity = 3 m/s^2

<h2>_____________________________________</h2><h2>SOLUTION:</h2>

By the equation of kinetic energy,

                                       

                                         K.E = \frac{1}{2} mv^2

Where,

            K.E is kinetic energy

            m is mass

            v is velocity

<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>

 

Directly substitute the variables in the equation,

                                       

                                       K.E = \frac{1}{2}x4x5^2

Simplify the equation,

                                       K.E = 50 J

<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>

                                           

 Directly substitude the variable in the equation,

                                                           

                                        K.E = \frac{1}{2}x6x4^2

Simplify the equation,

                                        K.E = 48J

<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />

Substitute the variables in the equation,

                                         

                                         K.E = \frac{1}{2}x8x3^2

Simplify the Equation,

                                         

                                         K.E = 36J

<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />

Substitute the variable,

                                        K.E = \frac{1}{2}x 2x7^2

Simplify the equation,

                                     

                                        K.E = 49J

<h2>_____________________________________</h2>

As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.

<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />
6 0
2 years ago
A net force of 20 N acting on a wooden block produces an
Ymorist [56]

Answer:

From the second law of motion:

F = ma

we are given that the force applied on the block is 20N and the block accelerates at an acceleration of 4 m/s/s

So, F=  20N   and  a = 4 m/s/s

Replacing the variables in the equation:

20 = 4* m

m = 20 / 4

m = 5 kg

5 0
3 years ago
1. A DC-10 jumbo jet maintains an airspeed of 550 mph in a southwesterly direction. The velocity of the jet stream is a constant
Vladimir79 [104]

Answer:

The magnitude of actual velocity is <u>496.67 mph</u> and its direction is <u>51.54° with the x axis in the third quadrant</u>.

Explanation:

Given:

Speed of jumbo jet in southwesterly direction (v_j) = 550 mph

Velocity of jet stream from west to east direction (v_s)=80\ mph

First let us draw a vectorial representation of the above velocity vectors.

Consider the south direction as negative y axis and west direction as negative x axis.

From the diagram,

The velocity of the jet can be represented as:

\vec{v_j}=-550\cos(45)\vec{i}+(-550\sin(45)\vec{j} )\\\\\vec{v_j}=-388.91\vec{i}-388.91\vec{j}\ mph

Similarly, the velocity of the stream is, \vec{v_s}=80\vec{i}

Now, the vector sum of the above two vectors gives the actual velocity of the aircraft. So, the resultant velocity is given as:

\vec{v}=\vec{v_j}+\vec{v_s}\\\\\vec{v}=-388.91\vec{i}-388.91\vec{j}+80\vec{i}\\\\\vec{v}=(-388.91+80)\vec{i}-388.91\vec{j}\\\\\vec{v}=(-308.91)\vec{i}-388.91\vec{j}

Now, magnitude is given as the square root of sum of the squares of the 'i' and 'j' components. So,

|\vec{v}|=\sqrt{(-308.91)^2+(-388.91)^2}\\\\|\vec{v}|=496.67\ mph

As the horizontal and vertical components of actual velocity negative, the resultant vector makes an angle \theta with the x axis in the third quadrant.

The direction is given as:

\theta=\tan^{-1}(\frac{v_y}{v_x})\\\\\theta=\tan^{-1}(\frac{-388.91}{-308.91})\\\\\theta=51.54\°(Third\ quadrant)

Therefore, the magnitude of actual velocity is 496.67 mph and its direction is 51.54° with the x axis in the third quadrant.

5 0
3 years ago
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