There are 10⁹ picoseconds in 1 Ms
1 picosecond= 10¹² s
1 Ms = 10⁻³ s
so the number of picoseconds in one Ms=(10⁻³ s/1 Ms) * (10¹² Ps/ 1 s)=10⁹
Thus there are 10⁹ picoseconds in 1 Ms
Answer:
0.3 seconds
Explanation:
When we walk, our legs alternatively swing forward about the hip joint as a pivot. In this motion the leg is acting approximately as a physical pendulum. Treating the leg as a thin uniform rod of length 0.80 m,
To find the time it takes for the leg to swing forward, where g = 9.8 m/s^2
Let's use the simple pendulum formula which says that:
T = 2π( sqrt ( L/g))
T = 2π[sqrt (0.8/9.8)]
T = 2π × 0.082
T = 0.5129
For the leg to swing forward only, the number of complete oscillations will be half.
Period T = time t ÷ number of complete oscillations. That is,
T = t ÷ 1/2
0.5129 = t ÷ 1/2
t = 0.5129 × 1/2
Time t = 0.256 seconds.
Therefore, the time it takes for the leg to swing forward is 0.3 seconds approximately
Answer:
Explanation:
The equation for centripetal acceleration is 
.
We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.
Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference 
and the period T, then we have:
Putting all together:
Answer: Here's your answer friend,
Explanation:
1.Solid to Liquid --When a solid is heated the particles gain energy and start to vibrate faster and faster. ... Although the particles are still loosely connected they are able to move around. At this point the solid is melting to form a liquid. The particles in the liquid are the same as in the solid but they have more energy.
2.Liquid to Gas--Vaporization occurs when a substance changes from a liquid to a gas. The molecules in a liquid are in constant motion while staying relatively close together due to intermolecular forces. When an increase in temperature occurs, the molecules' kinetic energy also increases.
Answer:
3801.13 N
Explanation:
Pressure exerted on a surface is equivalent to applied force divided by the cross sectional area. Then, the applied force will be equal to the product of the pressure exerted and the cross sectional area.
Where given:
Atmospheric pressure (P1) = 1.013*10^5 Pa
T1 = 20+273.15 = 293.15 K
P2 = ?
T2 = 120+273.15 = 393.15 K
Using the gas equation: P1/T1 = P2/T2
Therefore, P2 = P1*T2/T1 = 1.013*10^5 *393.15/293.15 = 13.6*10^4 Pa
The net pressure = P2 - P1 = 13.6*10^4 - 1.013*10^5 = 34.6 kPa
The net force 
Area = 0.11 m^2
Thus:
The net force 
= 3801.13 N
