Answer:
(a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.
Explanation:
Given that,
Charge = 10.1 μC
Capacitor C₁ = 1.10 μF
Capacitor C₂ = 1.92 μF
Capacitor C₃ = 1.10 μF
Potential V₁ = 51.5 V
Let V₁ and V₂ be the potentials on the two plates of the capacitor.
(a). We need to calculate the potential on the negative plate of the 1.10 μF capacitor
Using formula of potential difference
Put the value into the formula
The potential on the second plate
(b). We need to calculate the equivalent capacitance of the two capacitors
Using formula of equivalent capacitance
Put the value into the formula
Hence, (a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.
The resultant of the acceleration can be found using:
a = √(ax² + ay²)
a = √(1.5² + 3.7²)
a = 3.99 m/s²
v = u + at, u = 0
v = 3.99 x 6.4
v = 25.5 m/s
Answer:
The frequency of the wave is 5.0Hz
Explanation:
The frequency of a wave is the number of oscillations or revolutions made in a second.
Answer:Let’s assume that, after the soccer ball is kicked and moves through its trajectory, it first makes contact with level ground a horizontal distance of 35 meters from where it was kicked. Let’s also assume that we can neglect air resistance. The time, t, that the soccer ball is in the air until it first contacts the ground can be found from the equation h = (1/2)gt^2 which can be rewritten as t = sqrt(2h/g) where h is the vertical distance the ball falls which is the height of the hill since the ball was kicked horizontally, and g is the acceleration of gravity which is 9.8 m/s^2. So t = sqrt(2(22)/9.8) = 2.12 seconds. In that time, the ball travelled 35 meters so its horizontal velocity was 35 meters/2.12 seconds = 16.5 meters/second.
Explanation:
Kepler's third law of planetary motion states that:
"The ratio between the cube of the orbital radius of the planet and the square of the orbital period is constant". In formulas:
where r is the orbital radius and T the orbital period.
Since this ratio is constant for every planet, we see that when the orbital radius r is larger (i.e. when the planet is farther from the Sun), the orbital period T is larger: this means the planet takes more time to complete one revolution around the Sun, so it moves slower.
Therefore, the correct option is:
<span>A planet moves slowest when it is farthest from the sun.</span>