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irga5000 [103]
3 years ago
12

What is the value of the expression 10 5/8 - (1/2) + 2(4)?

Mathematics
1 answer:
swat323 years ago
7 0

Answer:

     m        

Step-by-step explanation:

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T+b = 41<br> t = 2b+2<br> Solve for t and b
erastovalidia [21]

Answer: b=13, t=29

Step-by-step explanation:

Substituting the first equation into the second,

2b+2+b=41\\\\3b+2=41\\\\3b=39\\\\b=13\\\\\implies t=2(13)+2=29

3 0
2 years ago
Point B is between A and C BC = 11 CM and AC = 17 CM what is AB
yaroslaw [1]
AB is 6 because you just subtract BC from AC to find the other missing length.
5 0
3 years ago
PLEASE HELP GIVONG BRAINLIEST PLSSSSSSSHDHFHFHFJFJJFJRJRHR AHHHHHH
34kurt

Hi there hopefully this helps!

-----------------------------------------------------------------------------------------------------

Answer: C.

Explanation:

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The mean: 10.4

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The mean: 7.43.

3 0
3 years ago
If a number has an absolute value equal to 3.06 that number could be____?
bonufazy [111]
D

Absolute Value of a number is the positive of whatever to total value is. For example |-12| = 12, and |32| = 32
8 0
3 years ago
Read 2 more answers
The circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm. (a) Use differentials to estimate the ma
andreev551 [17]

The maximum error in the calculated surface area is 24.19cm² and the relative error is 0.0132.

Given that the circumference of a sphere is 76cm and error is 0.5cm.

The formula of the surface area of a sphere is A=4πr².

Differentiate both sides with respect to r and get

dA÷dr=2×4πr

dA÷dr=8πr

dA=8πr×dr

The circumference of a sphere is C=2πr.

From above the find the value of r is

r=C÷(2π)

By using the error in circumference relation to error in radius by:

Differentiate both sides with respect to r as

dr÷dr=dC÷(2πdr)

1=dC÷(2πdr)

dr=dC÷(2π)

The maximum error in surface area is simplified as:

Substitute the value of dr in dA as

dA=8πr×(dC÷(2π))

Cancel π from both numerator and denominator and simplify it

dA=4rdC

Substitute the value of r=C÷(2π) in above and get

dA=4dC×(C÷2π)

dA=(2CdC)÷π

Here, C=76cm and dC=0.5cm.

Substitute this in above as

dA=(2×76×0.5)÷π

dA=76÷π

dA=24.19cm².

Find relative error as the relative error is between the value of the Area and the maximum error, therefore:

\begin{aligned}\frac{dA}{A}&=\frac{8\pi rdr}{4\pi r^2}\\ \frac{dA}{A}&=\frac{2dr}{r}\end

As above its found that r=C÷(2π) and r=dC÷(2π).

Substitute this in the above

\begin{aligned}\frac{dA}{A}&=\frac{\frac{2dC}{2\pi}}{\frac{C}{2\pi}}\\ &=\frac{2dC}{C}\\ &=\frac{2\times 0.5}{76}\\ &=0.0132\end

Hence, the maximum error in the calculated surface area with the circumference of a sphere was measured to be 76 cm with a possible error of 0.5 cm is 24.19cm² and the relative error is 0.0132.

Learn about relative error from here brainly.com/question/13106593

#SPJ4

3 0
2 years ago
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