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3 years ago

Finally, it is time to return to Earth and review how scientists here classify organisms:

Chemistry

1 answer:

lilavasa [31]3 years ago

6 0

5. Eubacteria

6. Plantae

7. Animalia

8. Protist (technically not a kingdom)

9. Archaebacteria

10. Fungi

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Iron is biologically important in the transport of oxygen by red blood cells from the lungs to the various organs of the body. I

Aneli [31]

Answer : The number of iron atoms present in each red blood cell are, $1.077\times 10^9$

Explanation :

First we have to calculate the moles of iron.

$\text{Moles of iron}=\frac{\text{Mass of iron}}{\text{Molar mass of iron}}=\frac{2.90g}{55.85g/mole}=0.0519moles$

Now we have to calculate the number of iron atoms.

As, 1 mole of iron contains $6.022\times 10^{23}$ number of iron atoms

So, 0.0519 mole of iron contains $0.0519\times 6.022\times 10^{23}=3.125\times 10^{22}$ number of iron atoms

Now we have to calculate the number of iron atoms are present in each red blood cell.

Number of iron atoms are present in each red blood cell = $\frac{\text{Number of iron atoms}}{\text{Total number of red blood cells}}$

Number of iron atoms are present in each red blood cell = $\frac{3.125\times 10^{22}}{2.90\times 10^{13}}$

Number of iron atoms are present in each red blood cell = $1.077\times 10^9$

Therefore, the number of iron atoms present in each red blood cell are, $1.077\times 10^9$

6 0

3 years ago

An iron smoothing out the wrinkles in pants ? CONVECTION,RADIATION,CONDUCTION?

nexus9112 [7]

Answer:

Conduction i think-

3 0

3 years ago

Read 2 more answers

What category is most of the elements part of

rjkz [21]

Answer:

transition metals

Explanation:

they're the elements in yellow in the picture

6 0

3 years ago

How many formula units are in 0.96 moles of H2O

never [62]

Answer:

18.02 amu

Explanation:

6 0

3 years ago

Need help please?!!!!!

puteri [66]

(a) 33.6 L of oxygen would be produced.

(b) 106 grams of $Na_2CO_3$ would be needed

<h3>Stoichiometric calculations</h3>

1 mole of gas = 22.4 L

(a) From the equation, 2 moles of $KClO_3$ produce 3 moles of $O_2$ . 1 mole of $KClO_3$ will, therefore, produce 1.5 moles of $O_2$ .

1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L

(b) 22.4 L of $CO_2$ is produced at STP. This means that 1 mole of the gas is produced.

From the equation, 1 mole of $CO_2$ requires 1 mole of $Na_2CO_3$ .

Molar mass of $Na_2CO_3$ = (23x2)+ (12)+(16x3) = 106 g/mol

Mass of 1 mole $Na_2CO_3$ = 1 x 106 = 106 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

6 0

2 years ago