Answer: Ionic substances would be good conductors since they dissolve in water and form ions.
Explanation:
Conductors can be defined as those materials which can allow the electricity to flow through them. The conductors also allow the transmission of heat and light from one to another source. They conduct electricity by allowing the electrons to flow through them easily.
The ionic substances can be good conductors because these can be dissolved in water and they will produce ions. The positively-charged ions will be attracted towards the negative electrode whereas the negatively charged ions to the positive electrode.
Note that
The heating value of standard coal is about 30,080 kJ/kg
1 L of water has a mass of 1.0 kg
The mass of 15 L of water = 15 kg.
The latent heat of vaporization of water is about 2260 kJ/kg,
The energy required to boil 15 L of water is
(2260 kJ/kg)*(15 kg) = 33900 kJ
The mass of coal required to provide this energy is
(33900 kJ)/(30080 kJ/kg) = 1.127 kg
Because 1 kg = 2.205 lb, the mass of coal required is
(1.127 kg)*(2.205 lb/kg) = 2.485 lb
Answer: 2.49 lb (nearest hundredth)
<span>At a depth of 34 feet the diver experiences 2 atmospheres of pressure.
At a depth of 68 feet the diver is experiencing 3 atmospheres.
At a depth of 102 feet the diver is experiencing 4 atmospheres of pressure.
At one atmosphere of pressure the body is mildy compressed. As the diver descends the divers body will undergo increased compression instead of being squashed.</span>
Answer:
I Don't Know.
Explanation: I'm Sorry, But I'm Not Good At This Subject. Atleast I'm Being Honest.
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of cysteine = 150 mg = 150 x 10⁻³ g
Molar mass of cysteine = 121.16 g/mol
Moles of cysteine = 150 x 10⁻³ g / 121.16 g/mol
= 1.238 x 10⁻³ mol
Cysteine has chemical formula as C₃H₇NO₂<span>S.
Hence, 1 mole of </span>C₃H₇NO₂S produces 7 moles of H atoms.
Hence, moles of H atoms present in the sample = 1.238 x 10⁻³ mol x 7
= 8.666 x 10⁻³ mol
According to the Avogadro's constant 1 mole of substance has 6.022 × 10²³ particles.
Hence,
number of H atoms in the sample = 8.666 x 10⁻³ mol x 6.022 × 10²³ mol
= 5.219 x 10²¹
