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3 years ago

Which factor is generally responsible for high melting points?

Chemistry

2 answers:

nikdorinn [45]3 years ago

8 0

Answer: Option (A) is the correct answer.

Explanation:

Melting point is defined as the point where a solid substance starts to convert into a liquid state.

For example, ice starts to melt at a temperature above 0 degree celsius.

More strong is the intermolecular forces of attraction present in a substance more will be the heat required by it to break the bonds between its particles. So, that its state can be changed.

For example, a solid substance required more heating as compared to a liquid substance to change its state.

Thus, we can conclude that high intermolecular forces of attraction is generally responsible for high melting points.

vlabodo [156]3 years ago

7 0

A. High intermolecular forces of attraction. If there are high intermolecular forces, the molecules will need large energies to escape into the liquid. The substance will nave a high melting point.

The other options are incorrect because they are weak forces. They would cause low melting points.

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The isomerization reaction, ch3nc → ch3cn, is first order and the rate constant is equal to 0.46 s-1 at 600 k. what is the conce

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㏑[A] / 0.3 = - 0.46 * 12
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Convert 63.3 kg to grams

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Answer:

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Explanation:

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Write the balanced chemical equation for the reaction between aqueous sodium carbonate and

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Answer:

2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + CO2 (g) + H2O (l)

Explanation:

This question is asking to write and balance an equation between between aqueous sodium carbonate (Na2CO3) and aqueous nitric acid (HNO3). The equation is as follows:

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However, this equation is not balanced as the number of atoms of each element must be the same on both sides of the equation. To balance the equation, one will make use of coefficients as follows:

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3 years ago

When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e

sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

2 Al(s) + 3Cl₂(g) ⇒ 2AlCl₃

Process

a) Calculate the molar mass of the reactants

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion Al/Cl₂ = 53.96/212.7 = 0.254

Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

53.96 g of Al ------------------ 212.7 g of Cl₂

40.5 g of Al ------------------- x

x = (40.5 x 212.7) / 53.96

x = 8614.35 / 53.96

x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

= 53.057 g

d) Calculate the moles of Cl

35.45 g of Cl ----------------- 1 mol

53.057 g of Cl --------------- x

x = (53.057 x 1)/35.45

x = 1.49 mol of Cl₂

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