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Free_Kalibri [48]
3 years ago
10

Which factor is generally responsible for high melting points?

Chemistry
2 answers:
nikdorinn [45]3 years ago
8 0

Answer: Option (A) is the correct answer.

Explanation:

Melting point is defined as the point where a solid substance starts to convert into a liquid state.

For example, ice starts to melt at a temperature above 0 degree celsius.

More strong is the intermolecular forces of attraction present in a substance more will be the heat required by it to break the bonds between its particles. So, that its state can be changed.

For example, a solid substance required more heating as compared to a liquid substance to change its state.

Thus, we can conclude that high intermolecular forces of attraction is generally responsible for high melting points.

vlabodo [156]3 years ago
7 0

A. High intermolecular forces of attraction. If there are high intermolecular forces, the molecules will need large energies to escape into the liquid. The substance will nave a high melting point.

The other options are <em>incorrect </em>because they are <em>weak force</em>s. They would cause <em>low melting points</em>.

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Copper(II) sulfate pentahydrate, CuSO4 ·5 H2O, (molar mass 250 g/mol) can be dehydrated by repeated heating in a crucible. Which
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Answer:

The water lost is 36% of the total mass of the hydrate

Explanation:

<u>Step 1:</u> Data given

Molar mass of CuSO4*5H2O = 250 g/mol

Molar mass of CuSO4 = 160 g/mol

<u>Step 2:</u> Calculate mass of water lost

Mass of water lost = 250 - 160 = 90 grams

<u>Step 3:</u> Calculate % water

% water = (mass water / total mass of hydrate)*100 %

% water = (90 grams / 250 grams )*100% = 36 %

We can control this by the following equation

The hydrate has 5 moles of H2O

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The water lost is 36% of the total mass of the hydrate

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Answer:

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Example: Consider the following reaction ...

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In terms of molecules, there are 4 molecules on the left (3 molecular hydrogens (H₂) and 1 molecular nitrogen (N₂) and 2 molecules of ammonia on the right side of equation arrow. ∑reactant molecules ≠ ∑product molecules.

In terms of mass of reactants & mass of products, the 3H₂ + N₂ => 6amu + 28amu = 34amu & mass of products (2NH₃) => 2(14amu) + 6(1amu) = 34amu for sum of product masses.

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