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AlexFokin [52]
4 years ago
13

Which of the following processes would you predict to have an increase in entropy?

Chemistry
2 answers:
arlik [135]4 years ago
3 0

Among the choices given, the best answer is the third option. Melting ice shows an increase in entropy. Entropy is the degree of disorderliness in a system. Among the phases, solid has the most ordered structure which means it has the least entropy. The ice melting shows a phase change from solid to liquid. Liquid molecules are more disorganized than the solid thus there is an increase in entropy.

Studentka2010 [4]4 years ago
3 0

Answer: melting ice

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

1. condensation of water : Condensation process is a process where gaseous state changes to liquid state., thus decreasing randomness and decreasing entropy.

2. Freezing water : Freezing process is a process where liquid state changes to solid state, thus decreasing randomness and decreasing entropy.

3. melting ice: Fusion process is a process where solid state changes to liquid state, thus increasing randomness and increasing entropy.

4. deposition of CO_2: deposition process where gaseous state changes to solid state by escaping liquid state, thus decreasing randomness and decreasing entropy.

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BlackZzzverrR [31]

The complete balanced chemical reaction is written as:

AgNO3 + KCl ---> AgCl + KNO3 

where AgCl is our precipitate

 

So calculating for moles of AgCl produced: MM AgCl = 143.5 g/mol

moles AgCl = 0.326 g / (143.5 g/mol) = 2.27 x 10^-3 mol

we see that there is 1 mole of Ag per 1 mole of AgCl so:

moles Ag = 2.27 x 10^-3 mol

 

The molarity is simply the ratio of number of moles over volume in Liters, therefore:

Molarity = 2.27 x 10^-3 mol / 0.0977 L

<span>Molarity = 0.0233 M</span>

4 0
3 years ago
quizlet a basement is successfully sealed so that more radon may not enter the space, but 5.7×107 radon atoms are already trappe
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After 25 days, it remains radon 5.9x10^5 atoms.

Half-life is the time required for a quantity (in this example number of radioactive radon) to reduce to half its initial value.

N(Ra) = 5.7×10^7; initial number of radon atoms

t1/2(Ra) = 3.8 days; the half-life of the radon is 3.8 days

n = 25 days / 3.8 days

n = 6.58; number of half-lifes of radon

N1(Ra) = N(Ra) x (1/2)^n

N1(Ra) = 5.7×10^7 x (1/2)^6.58

N1(Ra) = 5.9x10^5; number of radon atoms after 25 days

The half-life is independent of initial concentration (size of the sample).

More about half-life: brainly.com/question/1160651

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6 0
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