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AlexFokin [52]
3 years ago
13

Which of the following processes would you predict to have an increase in entropy?

Chemistry
2 answers:
arlik [135]3 years ago
3 0

Among the choices given, the best answer is the third option. Melting ice shows an increase in entropy. Entropy is the degree of disorderliness in a system. Among the phases, solid has the most ordered structure which means it has the least entropy. The ice melting shows a phase change from solid to liquid. Liquid molecules are more disorganized than the solid thus there is an increase in entropy.

Studentka2010 [4]3 years ago
3 0

Answer: melting ice

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

1. condensation of water : Condensation process is a process where gaseous state changes to liquid state., thus decreasing randomness and decreasing entropy.

2. Freezing water : Freezing process is a process where liquid state changes to solid state, thus decreasing randomness and decreasing entropy.

3. melting ice: Fusion process is a process where solid state changes to liquid state, thus increasing randomness and increasing entropy.

4. deposition of CO_2: deposition process where gaseous state changes to solid state by escaping liquid state, thus decreasing randomness and decreasing entropy.

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2 years ago
A hydrocarbon contains 85.7% carbon and the remainder
Viefleur [7K]

Answer:

CH₂ ;  67.1 %

Explanation:

To determine the empirical formula we need to find what the mole ratio is in whole numbers of the atoms in the compound. To do that we will first need the atomic weights of C and H and then perform our calculation

Assume 100 grams of the compound.

# mol C = 85.7 g / 12.01 g/mol = 7.14 mol

# mol H = 14.3 g /  1.008 g/mol = 14.19 mol

The proportion is 14.9 mol H/ 7.14 mol C = 2 mol H/ 1 mol C

So the empirical formula is CH₂

For the second part we will need to first calculate the theoretical yield for the 12.03 g NaBH₄  reacted and then calculate the percent yield given the 0.295 g B₂H₆ produced.

We need to calculate the moles of  NaBH₄ ( M.W = 37.83 g/mol )

1.203 g  NaBH₄ / 37.83 g/mol =  0.0318 mol

Theoretical yield from balanced chemical equation:

0.0318 mol NaBH₄ x 1 mol B₂H₆ / mol NaBH₄ = 0.0159 mol B₂H₆

Theoretical mass yield B₂H₆ = 0.0159 mol x 27.66 g/ mol =  0.440 g

% yield = 0.295 g/ 0.440 g x 100 = 67.1 %

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