Answer:
The answer is "6L"
Explanation:
Formula:
Values:
Elaine's teacher gave her two cubes and asked her to record as many observations as possible. The data table of her observations
is shown on the above.
A. Calculate the volume; a density of 0.33 g/cm^3; the temperature of 25°C; Same
B. Calculate the density; the volume of 27 cm^3; a density of 0m44 g/cm^3; Different
C. Calculate the temperature of the cube's surface; the temperature of 24° C; the volume of 27 cm^3 can not he determined
D. Caluclate the density; density of 0.33 g/cm^3; density of 0.44 g/cm^3; Different 
A. Calculate the volume; a density of 0.33 g/cm^3; the temperature of 25°C; Same
B. Calculate the density; the volume of 27 cm^3; a density of 0m44 g/cm^3; Different
C. Calculate the temperature of the cube's surface; the temperature of 24° C; the volume of 27 cm^3 can not he determined
D. Caluclate the density; density of 0.33 g/cm^3; density of 0.44 g/cm^3; Different
1 answer:
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Answer: 50.7 grams
Explanation:
To calculate the moles, we use the equation:
a) moles of
The balanced chemical equation is:
is the limiting reagent as it limits the formation of product and
is in excess.
According to stoichiometry :
2 moles of give = 1 mole of
Thus 0.220 moles of give=
of
Mass of
Thus 50.7 g of will be formed.