Elaine's teacher gave her two cubes and asked her to record as many observations as possible. The data table of her observations
is shown on the above.
A. Calculate the volume; a density of 0.33 g/cm^3; the temperature of 25°C; Same
B. Calculate the density; the volume of 27 cm^3; a density of 0m44 g/cm^3; Different
C. Calculate the temperature of the cube's surface; the temperature of 24° C; the volume of 27 cm^3 can not he determined
D. Caluclate the density; density of 0.33 g/cm^3; density of 0.44 g/cm^3; Different 
A. Calculate the volume; a density of 0.33 g/cm^3; the temperature of 25°C; Same
B. Calculate the density; the volume of 27 cm^3; a density of 0m44 g/cm^3; Different
C. Calculate the temperature of the cube's surface; the temperature of 24° C; the volume of 27 cm^3 can not he determined
D. Caluclate the density; density of 0.33 g/cm^3; density of 0.44 g/cm^3; Different
1 answer:
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<u>Answer:</u> The temperature of the system will be 1622 K
<u>Explanation:</u>
The equation relating the pre-exponential factor and activation energy follows:
where,
D = diffusion coefficient =
= pre-exponential constant =
= activation energy of iron in cobalt = 273,300 J/mol
R = Gas constant = 8.314 J/mol.K
T = temperature = ?
Putting values in above equation, we get:
Hence, the temperature of the system will be 1622 K