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Taya2010 [7]
3 years ago
5

Wile E. Coyote wants to launch Roadrunner into the air using a long lever asshown below. The lever starts at rest before the Coy

ote steps onto one end and pivots around its center of mass. Roadrunner is standing on the other end, which is held up by a small piece of ground underneath. The lever has mass 1.2 kg and length 16 m, the Roadrunner has mass 3.2 kg, and there is no friction at the pivot point of the lever.
a) Draw free body diagrams for the lever, Coyote, and Roadrunner. Make sure to label where all of the forces act on the lever’s free body diagram.
b) What is the minimal mass that Coyote must have to cause the lever to start rotating?
c) The coyote actually has a mass of 18 kg. If the roadrunner goes flying when the lever gets to a 45∘ angle from the horizontal, what is the roadrunner’s speed at that time, assuming the pivot is frictionless?
d) (Optional/challenge) What is the angular acceleration just after Coyote steps onto the lever?

Physics
1 answer:
algol133 years ago
4 0

Answer:

Explanation:

Find attached the solution

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a magnet has a 20 cm magnetic field if a piece of metal is 18 cm from the magnet will it be attracted or not
mina [271]

Answer:

yes

Explanation:

The metal is closer than 20 cm to the magnet which is in the magnetic field.

4 0
4 years ago
Question 1(Multiple Choice Worth 2 points)
tia_tia [17]

Answer:

D

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the reason for each column is to show the electronic configuration of the elements in that column.

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3 0
3 years ago
At 19°C, a rod is exactly 19.11 cm long on a steel ruler. Both the rod and the ruler are placed in an oven at 280°C, where the r
Ratling [72]

Answer:

\alpha = 4.12 \times 10^{-5} per Degree C

Explanation:

As we know that when we increase the temperature of the rod and the ruler then in that case there will be change in the length of the both.

Due to this the ruler measurement is different from actual length of the rod

So by thermal expansion we know that

L = L_o(1 +\alpha \Delta T)

L = 19.11 (1 + \alpha(280 - 19))

L = 19.11(1 + 261\alpha)

Now for length of unit division of steel scale

1 unit = 1( 1 + \alpha_s \Delta T)

1 unit = (1 + (11 \times 10^{-6})(280 - 19))

1 unit = 1.0029

now the measured length from the scale is given as

L_{measured} = \frac{L}{1.0029}

L_{measured} = \frac{19.11(1 + 261\alpha)}{1.0029}

19.26 = \frac{19.11(1 + 261\alpha)}{1.0029}

\alpha = 4.12 \times 10^{-5} per Degree C

8 0
3 years ago
In general, the-------- the string or air column of a musical instrument is, the more harmonics are generated. shorter or longer
yanalaym [24]
Longer the air column is the more harmonics are created. due to the longer column the waves have more space to bounce off of the sides of the column to create more harmonics.
7 0
4 years ago
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An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximu
vovikov84 [41]

Answer:

Technician A

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An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximum = 932 mV; average = 442 mV. Technician A says that the engine is operating normally. Technician B says that the oxygen sensor is skewed too rich. Which technician is correct?

an oxygen sensor detects te amount of oyen in an engine at the exhaust pipe.

if the  oxygen sensor detects oxygen at the above boundary condition, ten the engine is in good working condition

6 0
3 years ago
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