How does the input distance of a third-class lever compare to the output distance
1 answer:
You might be interested in
Answer:
Double the current
Explanation:
The energy delivered by the heater is related to the current by the following relation:
E=
let R * t = k ( ∴ R and t both are constant)
so E= k
Now let:
E2= k I₂^2
E2= 4E
⇒ k I₂^2= 4* k
Cancel same terms on both sides.
I₂^2= 4*
taking square-root on both sides.
√I₂^2 = √4* I^2
⇒I₂= 2I
If we double the current the energy delivered each minute be 4E.
Good afternoon.
We have:
The function of velocity:
For t = 5 s:
We have:
The function of velocity:
For t = 5 s:
Answer:
Explanation:
The problem is solved using the law of conservation of energy,
So