1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fiesta28 [93]
3 years ago
7

HELP!!!!! PLEASE! :( GIVING 65 POINTS AND WILL GIVE BRAINLIEST.

Physics
1 answer:
Alja [10]3 years ago
5 0

Explanation:

The given problem should be solved using basic sedimentary laws proposed by Nicolas Steno and other group of geologists.

Some of the laws that would find application in this problem are:

  • Law of superposition of strata which states that "in an undeformed sequence of sedimentary rocks, the oldest strata is at the bottom and the youngest on top"
  • Law of lateral continuity states that "sedimentary rocks are laid down down horizontally and laterally in space until they taper at edges of basins"
  • Law of cross-cutting "events such as folding, fracturing, intrusion are younger than than the rock layers that they affect".

Based on this premise, we can derive the geologic column for the area:

                       Chart A                                               Chart B

                       <em> Erosion                                              Erosion</em>

1                             C                                                          a

2                             E                                                         e

3                             H                                                         h

3                      <em>   Erosion                                                   </em>m

4                           A                                                      <em>   Erosion</em>

5                            B                                                              c

6                            F                                                               j

7                            D                                                              l

8                            L                                                              g

9                            G                                                              k

10                           J                                                              f

11                            i                                                                i

12                                                                                          d

13                                                                                           b

The above was derived using the sedimentary laws for relative dating.

Observations 1

In Record A unconformity will occur between layers H and A

    Record B unconformity will occur between layers c and m

An unconformity is a huge break in the stratigraphic record. It is usually a time gap as a result of non-deposition of sediments, erosion of a rock layers amidst other factors.

The type of unconformity here is called an angular unconformity.

In this kind of unconformity, parallel beds are deposited on the tilted or folded layer below resulting in an angular discordance of some sort.

The surface between H and A is an erosional surface of the tilted beds in record A. This was followed by the deposition of new beds that are parallel to the tilted ones below.

In record be, a folded and eroded surface separate c and m.

Analysis 2

In record A, the rock layer K is older than F but younger than D. This rock layer has been tilted. This interpretation is based on the law of superposition of strata. If the sequences are reconstructed without the tilt, layer K will be on top of D and F will be on top of K.

Analysis 3

Layer c is younger than j but older than the parallel lying m on top of it. This geologic structure is called a synform. In synform, the rock strata has a concave shape. Usually, we can assume that this is a synformal syncline in which the youngest bed is at the core of the fold. This pits layer c as the youngest in the folded beds. The age increases outward in a synform.

Analysis 4

Layers C and E in record A are both eroded beds. Layer C has been eroded to the level of layer E.

We can establish that when layer C was exposed and eroded, the overburden on the earth was relieved and part of bed E re-adjusted up to the level of E.

Analysis 5

Reconstructing the geologic history of A

To form a sedimentary rock sequence, a basin must be available. Sedimentary basins are natural depressions on the earth crust in which sediments collects and are deposited.

Sediments i - A were deposited layer by layer into the basin. They became compacted and lithified to form sedimentary rocks.

With the passage of time, these layers became tilted by natural forces. This could be an earthquake, stress e.t.c

After the tilting, a period of non-deposition occurred in which the forces of denudation prevailed to cause the erosion of the bed when it was uplifted and exposed.

After this period, layers H-C was then deposited, compacted and lithified. The whole rock sequence was then uplifted exposing some rock layers. Erosion washed parts of layers C and E to what we can see in the present day.

Analysis 6

In record B, sequences b-c were laid in the basin of deposition where they were transformed into sedimentary rocks.

The rocks were then subjected to a compressive stress regime. The layers buckled and a synformal sycline fold formed.

After this period, the rock was uplifted and exposed. Erosion caused the washing away of parts of the top layer.

A period of deposition shortly followed and parallel layers m-a were deposited. This layer was then transformed into sedimentary rocks.

After this the layer became exposed and part of a was eroded to its present day level.

Learn more:

Sedimentary rocks brainly.com/question/9131992

Alignment of sedimentary rocks brainly.com/question/8655172

#learnwithBrainly

You might be interested in
The distance between two stations is 1995 Km. How much time will it take to cover the distance at an average speed of 19KM/hour
Flura [38]
105 hours or 4.375 days
5 0
4 years ago
Will give brainliest
NNADVOKAT [17]

I love science! if you need any more help let me know i cant guarantee i can help but i will try!

The correct answer is  "Some substances must be dissolved in water before they can be used".  

5 0
3 years ago
A golfer gives a ball a maximum initial speed of 51.5 m/s. how far does it go
nata0808 [166]

<u>Answer:</u>

Golf ball will go a maximum of 270.36 meter.

<u>Explanation:</u>

  Projectile motion has two types of motion Horizontal and Vertical motion.

 Vertical motion:

          We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

          Considering upward vertical motion of projectile.

          In this case, Initial velocity = vertical component of velocity = u sin θ, acceleration = acceleration due to gravity = -g m/s^2 and final velocity = 0 m/s.

         0 = u sin θ - gt

          t = u sin θ/g

     Total time for vertical motion is two times time taken for upward vertical motion of projectile.

     So total travel time of projectile = 2u sin θ/g

Horizontal motion:

   We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

   In this case Initial velocity = horizontal component of velocity = u cos θ, acceleration = 0 m/s^2 and time taken = 2u sin θ /g

  So range of projectile,  R=ucos\theta*\frac{2u sin\theta}{g} = \frac{u^2sin2\theta}{g}

  Now in the given problem

     A golfer gives a ball a maximum initial speed of 51.5 m/s. how far does it go

     u = 51.5 m/s, for maximum range θ = 45⁰

   So maximum distance reached = \frac{51.5^2sin(2*45)}{9.81}=270.36 meter

So it will go a maximum of 270.36 meter.

5 0
3 years ago
A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the bob's mass is do
Alborosie

1. B. T

The period of a simple pendulum is given by:

T=2\pi \sqrt{\frac{L}{g}} (1)

where

L is the length of the pendulum

g is the gravitational acceleration

From the formula, we notice that the period of the pendulum does not depend on the mass of the bob. Therefore, when the bob's mass is doubled, the period does not change.

2. C: sqrt(6)*T

In this case, the pendulum is brought to the moon, where the gravitational acceleration is

g'=\frac{g}{6}

If we substitute this value into the equation for the period (1), we find the new period of the pendulum:

T'=2\pi \sqrt{\frac{L}{g'}}=2\pi \sqrt{\frac{L}{(g/6)}}=\sqrt{6}(2\pi \sqrt{\frac{L}{g}})=\sqrt{6} T

3. B: It will no longer oscillate because there is no gravity in space

Explanation:

The motion (oscillation) of the pendulum is caused by the force of gravity, which "pulls" the bob towards the equilibrium position. If there is no gravity, then there is no force acting on the bob, therefore the pendulum can no longer oscillate.

So, the correct answer is

B: It will no longer oscillate because there is no gravity in space

4 0
4 years ago
Read 2 more answers
Express a speed of 50 kilometers per hour as meters per second<br>​
nignag [31]

Answer:

13.88 meters per second

6 0
3 years ago
Other questions:
  • What are physical forms in which a substance can exist?
    14·1 answer
  • A diver dives off of a raft - what happens to the diver? the raft? how does this relate to newton's third law? action force: ___
    5·2 answers
  • A 230 kg steel crate is being pushed along a cement floor. The force of friction is 480 N to the left and the applied force is 1
    8·2 answers
  • A person weighing 800 newtons travels to another planet with twice the mass and twice the radius of earth. what is the person's
    13·2 answers
  • I stretch a rubber band and "plunk" it to make it vibrate in its fundamental frequency. I then stretch it to twice its length an
    9·1 answer
  • WILL GIVE BRAINLY!!!!!!! Question: if a bird flies 100 meters in two minutes what is the bird's speed
    7·2 answers
  • an 18 ohm resistor and a 6 ohm resistor are connected in parallel to a battery, and the current in the 18 ohm resistor is found
    11·1 answer
  • A dog pulls on a pillow with a force of 5 N at an angle of 37o to the horizontal. Find the x and y components of this force.​
    6·1 answer
  • A mail carrier walked six blocks to the north, one block to the east, and then six blocks to the south. What was the mail carrie
    6·1 answer
  • Hurry!! The first important thing about hiking is that you tell someone where you are going and _________.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!