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3 years ago

What is the least possible initial kinetic energy kmin the oxygen atom could have and still excite the cesium atom?

1 answer:

5 0

If perfectly elastic there would be no energy left over for exciting the atom. if the collision were partially elastic, then some of the initial kinetic energy would be converted into internal energy,

hope this help

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The kinetic energy of a 10 Kg ball rolling at 10 meters per second is how many joules

Ulleksa [173]

Answer: 500 joules

Explanation:

Given that

Mass of ball = 10kg

kinetic energy = ?

velocity of the ball = 10m/s

Kinetic energy is the energy possessed by a moving object. It is measured in joules, and depends on the mass (m) of the object and the velocity (v) by which it moves

i.e K.E = 1/2mv²

K.E = 1/2 x 10kg x (10m/s)²

K.E = 0.5 x 10kg x (10m/s)²

K.E = 5 x 100

K.E = 500 joules

Thus, the kinetic energy of the ball is 500 joules

6 0

4 years ago

Students perform an experiment in which they drop two eggs with equal mass from a balcony. in the first trial, the egg hits the

german

The impulse was greater in the first experiment because the egg broke.

<h3>What is impulse?</h3>

The term impulse is defined a the product of the force and time. We know that the impulse is high when a large force acts for a short time.

From the experiment if the students, we can conclude that the impulse was greater in the first experiment because the egg broke.

Learn more about impulse:brainly.com/question/16980676

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6 0

2 years ago

What is a limited resource?

Artemon [7]

Something that there is only so many of or not enough of

7 0

3 years ago

Read 2 more answers

A real heat engine operates between temperatures TcTcT_c and ThThT_h. During a certain time, an amount QcQcQ_c of heat is releas

Nookie1986 [14]

The maximum amount of work performed is

$W_{max}=\frac{T_H-T_C}{T_C}Q_C$

Explanation:

The efficiency of a real heat engine is given by the equation:

$\eta = 1-\frac{T_C}{T_H}$ (1)

where

$T_C$ is the temperature of the cold reservoir

$T_H$ is the temperature of the hot reservoir

However, the efficiency of a real heat engine can be also written as:

$\eta = \frac{W_{max}}{Q_H}$

where

$W_{max}$ is the maximum work done

$Q_H$ is the heat absorbed from the hot reservoir

$Q_H$ can be written as

$Q_H=W_{max}+Q_C$

where

$Q_C$ is the heat released to the cold reservoir

So the previous equation can be also written as

$\eta=\frac{W_{max}}{W_{max}+Q_C}$ (2)

By combining eq.(1) and (2) we get

$1-\frac{T_C}{T_H}=\frac{W_{max}}{W_{max}+Q}$

And re-arranging the equation and solving for $W_{max}$ , we find

$W_{max}=\frac{T_H-T_C}{T_C}Q_C$

Learn more about work and heat:

brainly.com/question/4759369

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8 0

3 years ago

Which describes why people on earth can see light from the stars in the sky that are so far away?

Ugo [173]

Yes, C is correct. It self explains itself as we know light travels through a vacuum ( doesn't need a medium) and light is a type of electromagnetic wave.

7 0

3 years ago