What is the least possible initial kinetic energy kmin the oxygen atom could have and still excite the cesium atom?
1 answer:
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The equilibrium constant of the reaction at 25⁰c will be 426827.5.
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- <u>Theory-</u>
<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.
The chemical equilibrium is given by for a general chemical reaction.
a. A+ b. B ⇌ c. C+ d. D,.
Kc =[C]c [D]d/[A]a [B]b.
<u>Gibb's free energy</u> :The second law of thermodynamics can be arranged in such a way that it gives a new expression when a chemical reaction happens at a constant temperature and constant pressure.
G=H-TS
- <u>Calculations</u>:-
T=25⁰c
G=51.4 x 10³J
k= equilibrium constant ,G=Gibbs free energy ,n= no. of moles ,R=Gas constant ,T=temperature ,Z=compressibility
k=51.4 x 10³ x 8.3 + 8.3 x 25
k=426827.5
To learn equilibrium constant-
<u>brainly.com/question/19669218</u>
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