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Serga [27]
3 years ago
9

What is the least possible initial kinetic energy kmin the oxygen atom could have and still excite the cesium atom?

Physics
1 answer:
Phoenix [80]3 years ago
5 0
If perfectly elastic there would be no energy left over for exciting the atom. if the collision were partially elastic, then some of the initial kinetic energy would be converted into internal energy,

hope this help
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When a metal element bonds with a non mental element they are known as ____ bond
frozen [14]

Answer:

ionic

Explanation:

ionic bond is when a metal and nonmetal are bonded together

metallic bond is when a two metal are bonded

covalent is nonmetal and nonmetal bond or idk

4 0
3 years ago
1.Narysuj obraz ołówka o długości 6 cm znajdującego się w odległości 8 cm od soczewki o ogniskowej 6 cm
Aliun [14]

Answer:

free quotes from carpet repair contractors at door in

Explanation:

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5 0
3 years ago
Answer these questions fast please:-
Andrew [12]
2.Cotton, polyester, nylon, rayon or can also be made by wool
5 0
3 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0 °C for the following reacti
Yakvenalex [24]

The equilibrium constant of the reaction at 25⁰c will be 426827.5.

<u />

  • <u>Theory-</u>

<u>Equilibrium constant</u> :The equilibrium constant comes from the chemical equilibrium law. For the chemical equilibrium state, at a fixed constant temperature, the ratio of the product of the reaction's multiplication to the concentration of its reactants' multiplication, and each is raised to the power to the corresponding coefficients of the elements in the reaction.

The chemical equilibrium is given by for a general chemical reaction.

a. A+ b. B ⇌ c. C+ d. D,.

Kc =[C]c [D]d/[A]a [B]b.

<u>Gibb's free energy</u> :The second law of thermodynamics can be arranged in such a way that it gives a new expression when a chemical reaction happens at a constant temperature and constant pressure.

G=H-TS

  • <u>Calculations</u>:-

T=25⁰c

G=51.4 x 10³J

\\\\k=GR+\frac{nRT}{Z} \\

k= equilibrium constant ,G=Gibbs free energy ,n= no. of moles ,R=Gas constant ,T=temperature ,Z=compressibility

Ideal.Situation=\left \{ {{Z=1} \atop {n=1}} \right.

\\\\\\k=GR+RT

k=51.4 x 10³ x 8.3 + 8.3 x 25

k=426827.5

To learn equilibrium constant-

<u>brainly.com/question/19669218</u>

#SPJ4

6 0
1 year ago
A 50.0-g ball traveling at 25.0 m/s bounces off a brick wall and
liubo4ka [24]

Answer:

13,400 m/s²

Explanation:

Average acceleration is the change in velocity over time:

a = Δv / t

a = (22.0 m/s − (-25.0 m/s)) / 0.00350 s

a = 13,400 m/s²

4 0
3 years ago
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