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lesantik [10]
4 years ago
6

A crate is pulled across a horizontal, frictionless floor by a rope. At the same time, the crate pulls back on the rope, in acco

rd with Newton's third law. Does the work done on the crate by the rope then equal zero?
Physics
1 answer:
Verdich [7]4 years ago
4 0

Answer:

Explanation:

If force F is applied on the crate , it will move with acceleration

a = F / m as no other force is acting on it .

This force is applied on the crate . work done by rope on crate  will be positive and equal to F x d where d is displacement .

The reaction force will apply on hand through rope. So work will also be done on hand by crate . This work will be negative as displacement in hand is opposite to direction of force on it.

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A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its<br><br> volume in m^3.
ANTONII [103]

Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

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