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ValentinkaMS [17]
3 years ago
8

A chemical formula uses the chemical symbol and dots representing electrons.

Physics
2 answers:
bogdanovich [222]3 years ago
7 0

Answer: FALSE

Explanation:

Ber [7]3 years ago
5 0

Answer:

False

Explanation:

A chemical formula uses chemical symbols to represent the elements in a chemical reaction. Each symbol has a number that tells how many atoms of each element there are and the ratios of atoms in a molecule.

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To measure the acceleration due to gravity on a distant planet, an astronaut hangs a 0.070-kg ball from the end of a wire. The w
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Answer:

g = 1.64m/s²

Explanation:

1.5m in 0.078s

V = 15 / 0.078

= 19.23m/s

Tension = mg

μ = 3.10 × 10⁻⁴

T = V²μ

mg =  V²μ

g =  V²μ / m

g = ((19.23)²(3.10 × 10⁻⁴)) / (0.070)

g = 1.64m/s²

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3 years ago
Can someone please answer 5-7
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5) 1/2*0.06*50^2
= 75J
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A machine with a mechanical advantage of 10 is used to produce an output force of 250 Newton’s. What input force is applied to t
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Answer:

que tue nesisitas

Explanation:

4 0
3 years ago
Solve the equation. 5x-5=10x+2
Veronika [31]

Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

-5=5x+2     (simplify)

-5-2=5x     (subtract 2 from both sides)

-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

x=-1.4    (simplify)

i would really appreciate getting a brainliest. anyways i hope this helped and have a great rest of your day/night!! :)

8 0
3 years ago
Read 2 more answers
A single-phase electrical load draws 600KVA at 0.6 power factor lagging. a) Find the real and reactive power absorbed by the loa
Whitepunk [10]

Answer:

(a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

Explanation:

Given that,

Power factor = 0.6

Power = 600 kVA

(a). We need to calculate the reactive power

Using formula of reactive power

Q=P\tan\phi...(I)

We need to calculate the \phi

Using formula of \phi

\phi=\cos^{-1}(Power\ factor)

Put the value into the formula

\phi=\cos^{-1}(0.6)

\phi=53.13^{\circ}

Put the value of Φ in equation (I)

Q=600\tan(53.13)

Q=799.99\ kVAR

(b). We draw the power triangle

(c). We need to calculate the reactive power of a capacitor to be connected across the load to raise the power factor to 0.95

Using formula of reactive power

Q'=600\tan(0.95)

Q'=9.94\ KVAR

We need to calculate the difference between Q and Q'

Q''=Q-Q'

Put the value into the formula

Q''=799.99-9.94

Q''=790.05\ KVAR

Hence, (a). The reactive power is 799.99 KVAR.

(c). The reactive power of a capacitor to be connected across the load to raise the power factor to 0.95 is 790.05 KVAR.

8 0
3 years ago
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