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4 years ago

If the speed of light in a vacuum is 1.2 times that of the speed of light in a

Physics

2 answers:

irinina [24]4 years ago

7 0

Refractive Index for the material is 1.2

Explanation:

Formula for Refractive index of the material (n) = speed of light in vacuum/speed of light in the material

Given detail is speed of light in vacuum = 1.2 (speed of light in the material)

⇒ Speed of light in vacuum/Speed of light in the material

= 1.2 = n

The refractive index and the index of refraction are same. It describes how light travels through a substance.

igomit [66]4 years ago

6 0

Answer:

Explanation:

Refractive index if denoted by n is different for different materials.

Let, the speed of light in vacuum = v₁= 3x10⁸m/s

refractive index of vacuum= n₁= 1

refractive index of second medium= n₂= 1.2

now according to Snell's law

n₁ / n₂ = v₂ / v₁

thus the speed of light in second medium with refractive index 1.2 will be

v₂ = v₁ (n₁ / n₂)= 3x 10⁸m/s(1/1.2)= 2.5x10⁸ m/s

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2 years ago

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3 years ago

A potential difference of 1.20 V will be applied to a 33.0 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (

Nostrana [21]

Answer:A) Current = 1.739A, B)current density, J = 2.147x10^6 A/m2

magnitude of electric field , E = 0.036 N/C

)rate of thermal energy, P =2.086W

Explanation:

Resistance = R = ρL/A

But the cross-section area of the wire. is given as

Diameter / 2 = 0.04/2 =0.02in to m = 0.02 / 39.37= 0.000508

A = πr^2 = π x 0.000508^2 = 8.10 x 10^-7

since resistivity of copper,ρ= 17x10-9 ohm.m

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= 1.739/8.1x10-7

= 2.147x10^6 A/m2

c)magnitude of electric field , E = Current density x resistivity =J ρ

E = 2.147 x 10^6 x 17 x 10^-9

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3 years ago

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