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enot [183]
3 years ago
10

Mrs. Washington left a 15% tip for a dinner that cost $36.80. About how much tip did Mrs. Washington leave?

Mathematics
1 answer:
atroni [7]3 years ago
7 0

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                 Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

  • Mrs. Washington left about $5.52 in tip.
  • You have to multiply 0.15 x 36.80 to get the amount.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

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Find the size of the angle <br> 3<br> x<br> .
AlexFokin [52]

Answer:

Given - Two angles measures 2x and 3x

To find - size of 3x

Solution -

2x + 3x = 360° ( Make reflex angle )

5x = 360°

x = 360/5

x = 72°

3x = 3 * 72 = 216°

8 0
3 years ago
If x and y are odd numbers such that 10&lt;x&lt;y14, what is value of x+y?
wel
I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
5 0
3 years ago
Hi can someone pls help it’s urgenttt
SVEN [57.7K]

Step-by-step explanation:

dont stress just move onto the next question :)

6 0
3 years ago
Read 2 more answers
Can someone help with this and explain answer please.
photoshop1234 [79]

Because the triangles are similar the ratio of all the sides would be the same. So you need to find the ratio of the common sides and then use that ratio to find the unkown side.

In this picture sides FG = 52, FV would be the same side and is 24.

Dividing 24/52 = 0.461, so the unkown side WV would be 0.444 of it's common side HG.

HG = 39

39 * 0.461= 18.

The answer is C. 18

3 0
3 years ago
Read 2 more answers
Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$
Viefleur [7K]

QUESTION 1

Given that:

f(x)=2x^2+3x-9,

g(x)=5x+11,

and

h(x)=-3x^2+1

Then;

f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)

f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1

Group similar terms;

f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1

Simplify;

f(x)-g(x)+h(x)=-x^2-2x-19

QUESTION 2

Given that;

f(x)=4x-7.

g(x)=(x+1)^2

and

s(x)=f(x)+g(x)

Substitute the functions;

s(x)=4x-7+(x+1)^2

Substitute x=3

s(3)=4(3)-7+(3+1)^2

s(3)=12-7+(4)^2

s(3)=5+16

s(3)=21

QUESTION 3

Given:

f(x)=3x+2

g(x)=x^2-5x-1

f(g(x))=f(x^2-5x-1)

This implies that;

f(g(x))=3(x^2-5x-1)+2

Expand the parenthesis;

f(g(x))=3x^2-15x-3+2

f(g(x))=3x^2-15x-1

QUESTION 4

The given function is;

f(x)=3(x-6)^2+1

Let

y=3(x-6)^2+1

\Rightarrow y-1=3(x-6)^2

\Rightarrow \frac{y-1}{3}=(x-6)^2

\Rightarrow \sqrt{\frac{y-1}{3}}=x-6

\Rightarrow x=6+\sqrt{\frac{y-1}{3}}

The range is:

\frac{y-1}{3}\ge0

y-1\ge0

y\ge1

The interval notation is;

[1,+\infty)

6 0
3 years ago
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