A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity

1 answer:

3 0

A car with a velocity of 22 m/s is accelerated at a rate of 1.6 $m/s^2$ for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 $m/s^2$

We will be using the equation of motion:

v = u + at

$\therefore v=22+1.(6.8)$

$\Rightarrow v=22+10.88$

$\Rightarrow v=32.88 \ m/s$

The final velocity become 32.88 m/s.

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