Answer:
See below
Explanation:
Vertical position is given by
df = do + vo t - 1/2 a t^2 df = final position = 0 (on the ground)
do =original position = 2 m
vo = original <u>VERTICAL</u> velocity = 0
a = acceleration of gravity = 9.81 m/s^2
THIS BECOMES
0 = 2 + 0 * t - 1/2 ( 9.81)t^2
to show t =<u> .639 seconds to hit the ground </u>
During this .639 seconds it flies horizontally at 10 m/s for a distance of
10 m/s * .639 s =<u> 6.39 m </u>
Answer:
I'm not sure if the directions affect the speed tho
but I think it's 4? cause it's the speed relative to the ground
hope this helps:))
44.1 meters initial height of the rock.
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Inverse variation has the form of y=k/x. So you have the form of:
<span>V = k/P, plug in values of V and P to find k: </span>
<span>200 = k/32 </span>
<span>k = 6400 </span>
<span>So, your formula is V = 6400/P </span>
<span>V = 6400/20 </span>
<span>V = 320 </span>