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3 years ago

Q # 9 Find the circumference

Mathematics

1 answer:

kherson [118]3 years ago

3 0

Circumfernce: C=2*Pi*r
Pi=3.14
Radius of the circumference: r=3 m
C=2*3.14*(3 m)
C=18.84 m

Answer: First option 18.84 m

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Roy uses 1/4 cup of batter for each muffin. make a list of batter he will use depending on the number of muffins he makes.

evablogger [386]

1 muffin = 1/4 cup
2 muffins = 1/2 cup
3 muffins = 3/4 cup
4 muffins = 1 cup
5 muffins = 1 and 1/4 cup
6 muffins = 1 and 1/2 cup

5 0

4 years ago

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SOLVE THE QUESTION BELOW ASAP

qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have

$h(t)=-16t^{2}+98$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts, and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98$

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

$-16t^{2}+98=0$

$t^{2}=\frac{98}{16}$

square root both sides

$t=\pm\frac{\sqrt{98}}{4}$

$t=\pm7\frac{\sqrt{2}}{4}$

therefore

The t-intercepts are

$(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)$

$(-2.475,0), (2.475,0)$

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

$x=0$ ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point $(0,98)$

The y-intercept is the point $(0,98)$

The t-intercepts are $(-2.475,0), (2.475,0)$

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

$h(t)=-16(0)^{2}+98$

$h(0)=98\ ft$

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

Find the difference

$98\ ft-82\ ft=16\ ft$

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

$h(t)=-16(1)^{2}+98$

$h(1)=82\ ft$

For t=2

$h(t)=-16(2)^{2}+98$

$h(2)=34\ ft$

Find the difference

$82\ ft-34\ ft=48\ ft$

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from t=0 to t=1

8 0

3 years ago

You collect 140 total pieces of candy trick or treating and 35 of them are m&m's. What fraction of the candy is not m&m'

tekilochka [14]

$\frac{3}{4}$ of the candy is not m&m's.

Step-by-step explanation:

Given,

Total pieces of candy = 140

Number of m&m's = 35

Fraction = $\frac{Number\ of\ m&m}{Total\ pieces\ of\ candy}$

Fraction = $\frac{35}{140}$

Both 35 and 140 are multiples of 7, therefore,

Fraction of m&m's = $\frac{5}{20} = \frac{1}{4}$

As the number of m&m's fraction and not m&m's fraction will make a total of 1, therefore

fraction of m&m's + fraction of not m&m's = 1

fraction of not m&m's = 1 - fraction of m&m's

fraction of not m&m's = $1-\frac{1}{4}=\frac{4-1}{4}$

fraction of not m&m's = $\frac{3}{4}$

$\frac{3}{4}$ of the candy is not m&m's.

Keywords: fraction, subtraction

Learn more about fractions at:

#LearnwithBrainly

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3 years ago

Is the point (2,4) a solution of y <= -4x + 12?<br> HELP ASAP

Natasha2012 [34]

Answer:

yes

Step-by-step explanation:

y <= -4x + 12

(2,4) 4 <= -4*2 + 12 4<= 4 is true

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3 years ago

I'm confused, and I need help please ):

finlep [7]

X = 3 y = 4

so answer is 4

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4 years ago

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