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navik [9.2K]
3 years ago
7

A 15.5 kg mass vibrates in simple harmonic motion with a frequency of 9.73 Hz. It has a maximum displacement from equilibrium of

+14.6 cm at time, t = 0.00 s. The displacement from equilibrium of the mass at time, t = 1.25 s is_______?
Physics
1 answer:
algol [13]3 years ago
6 0

Answer:

12.14 cm

Explanation:

mass, m = 15.5 kg

frequency, f = 9.73 Hz

maximum amplitude, A = 14.6 cm

t = 1.25 s

The equation of the simple harmonic motion

y = A Sin ωt

y =  A Sin (2 x π x f x t)

put, t = 1.25 s, A = 14.6 cm, f = 9.73 Hz

y = 14.6 Sin ( 2 x 3.14 x 9.73 x 1.25)

y = 14.6 Sin 76.38

y = 12.14 cm

Thus, the displacement of the particle from the equilibrium position is 12.14 cm.

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Answer:

The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

Explanation:

Given that,

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Frequency = 2.15 GHz

(A). We need to calculate the magnetic field strength

Using formula of the magnetic field strength

B=\dfrac{2\pi mf}{e}

Where, f = frequency

e = charge of electron

Put the value into the formula

B=\dfrac{2\times3.14\times9.1\times10^{-31}\times2.15\times10^{9}}{1.6\times10^{-19}}

B=0.077\ T

(B). We need to calculate the energy of electron

Using formula of energy

E=\dfrac{1}{2}m(r\omega)^2

E=\dfrac{1}{2}\times9.1\times10^{-31}\times(1.31\times10^{-3}\times2\pi\times2.15\times10^{9})^2

E=1.4249\times10^{-16}\ J

The energy in eV

1 eV=1.6\times10^{-16}\ J

E=\dfrac{1.4249\times10^{-16}}{1.6\times10^{-16}}

E=0.8906\ eV

Hence, The magnetic field strength and the electrons' energy are 0.077 T and 0.8906 eV.

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3 years ago
A tennis ball is hit into the air with a racket. When is the balls kinetic energy the greatest?
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Velocity is maximum when the player hits the ball.

So kinetic energy is maximum when the player hits the ball.

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Explanation:

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option a

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3 years ago
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Answer:

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Explanation:

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For the engine in the problem, we know that

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