Most asteroids lie between the orbits of
2 answers:
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Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :
F = 0.607 N
(b) Area of wall,
Let P is the average pressure on that area. It is given by :
P = 0.202 Pa
Hence, this is the required solution.
- T_i=125°C=398K
- T_f=50°C=323K
- c=4184J/kg°K
- m=1kg
- ∆T=T_f-T_i=398-323=75K
Answer:
222.2N/m
Explanation:
Given parameters:
Elastic potential energy = 4000J
Extension = 6m
Unknown:
Spring coefficient = ?
Solution:
The elastic potential energy is the energy stored within a string.
It is expressed as;
EPE = k e²
k is the spring constant
e is the extension
4000 = x k x 6²
8000 = 36k
k = 222.2N/m