An airplane requires a much less force in order to get off the ground than a rocket does, since a rocket needs to exit Earth’s atmosphere.
Planes typically travel at much slower speeds that traditional rockets, as they are faced with varying restrictions that affect how quickly they fly.
Both forms of transportation, although very different in certain aspects, are similar in the fact that they both need to adhere to similar constraints. Although most airplanes aren’t faced with the challenge of exiting the atmosphere, they do need to focus on their fuel, their safety, etc. just as rockets do as well.
Answer:
s = 52.545 m
Explanation:
First, we calculate the distance covered during the 0.5 s when the driver notices the light and applies the brake.

where,
s₁ = distance covered between noticing light and applying brake = ?
v = speed = 18.6 m/s
t = time = 0.5 s
Therefore,

Now, we calculate the distance for the car to stop after the application of brakes. For that we use 3rd equation of motion:

where,
s₂ = distance covered after applying brake = ?
a = deceleration = - 4 m/s²
Vf = final speed = 0 m/s
Vi = initial speed = 18.6 m/s
Therefore,

So the total distance covered by the car before stopping is:

<u>s = 52.545 m</u>
D.multiple. because you always have to double check to see if its true or not. Majority rule.
Density is directly proportional to mass. So if there's less matter inside object, its density will also reduce.