The reaction between HNO3 and Ba(OH)2 is given by the equation below;
2HNO3 + Ba(OH)2 = Ba(NO3)2 + 2H2O
Moles of Barium hydroxide used;
= 0.200 × 0.039 l
= 0.0078 Moles
The mole ratio of HNO3 and Ba(OH)2 is 2: 1
Therefore; moles of nitric acid used will be;
= 0.0078 ×2 = 0.0156 moles
But; 0.0156 moles are equal to a volume of 0.10
The concentration of Nitric acid will be;
= (0.0156 × 1)/0.1
= 0.156 M
Answer:
4 moles of NH3 will be produced
Explanation:
The reaction expression is given as:
N₂ + 3H₂ → 2NH₃
We have to check that the equation of the reaction is balanced.
Then;
if 2 mole of N₂ reacts;
1 mole of N₂ will react with 3 mole of H₂ to produce 2 mole of NH₃
2 mole of N₂ will react with (2x3)mole of H₂ to produce (2x2)mole of NH₃
6mole of H₂ to produce 4 mole of NH₃
B, the opposing forces are the same, thus, the ball doesn't move back or forward.
I'm not the best with science but I believe the answer is B. Na.
