Answer:
-255.4 kJ
Explanation:
The free energy of a reversible reaction can be calculated by:
ΔG = (ΔG° + RTlnQ)*n
Where R is the gas constant (8.314x10⁻³ kJ/mol.K), T is the temperature in K, n is the number of moles of the products (n =1), and Q is the reaction quotient, which is calculated based on the multiplication of partial pressures by the partial pressure of the products elevated by their coefficient divide by the multiplication of the partial pressure of the reactants elevated by their coefficients.
C₂H₂(g) + 2H₂(g) ⇄ C₂H₆(g)
Q = pC₂H₆/[pC₂H₂ * (pH₂)²]
Q = 0.261/[8.58*(3.06)²]
Q = 3.2487x10⁻³
ΔG = -241.2 + 8.314x10⁻³x298*ln(3.2487x10⁻³)
ΔG = -255.4 kJ
Answer:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
Explanation:
There are many ways to balance a chemical equation. In this case, I will show you the algebraic method:
The first step is assign a letter to each compound:
a Fe₂O₃ + b CO → c Fe + d CO₂
Then, you must write the balance equations for each atom, thus:
<em>Fe: 2a = c</em>
<em>C: b = d</em>
<em>O: 3a + b = 2d</em>
The last step is assign a value to a letter. I, for example, will say that <em>a is 1, </em>and then find the values for the others letters, thus:
<em>Fe: 2a = c </em>if <em>a=1; c=2</em>
<em>O: 3a + b = 2d </em>if <em>a=1 → 3+b = 2d</em>
As b = d → <em>3+d = 2d; 3 = 2d - d; </em>3=d and 3=b
Thus, the balanced equation is:
Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂
I hope it helps!
Size and shape is a physical property of a substance
You can use the equation f(t) = 5*(1/2)^(t/8.02)
Then plug in 6.01 for time.There remains 2.97 mg in the sample.
Dipole moment can be defined as the product of separation of the ends of the dipole and the magnitude of the charges
