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likoan [24]
3 years ago
12

How can toxicant absorption be reduced after exposure to the skin? How can absorption be reduced for orally consumed chemicals?

Chemistry
1 answer:
zmey [24]3 years ago
4 0

Answer:

The toxicant absorbtion can be reduced after exposure to the skin the surrounding clothing shoes or gloves should be removed or torn off than the part of the body which was exposured to the toxicant should be immediatly washed using clean running water for a while, with cold shower being the most recommended splashing method. In case of absorption for orally consumed chemicals should check on any remaining toxicant residue and be removed from the mouth. Vomiting should be induced to patients that are still conscious by providing them with liquids that can provoke vomiting. This will help in removing the toxicant in the intestinal and reduce their effect. Gastric lavage should then be done to induce diarrhea.  

Explanation:

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Which answer best describes what is happening in the following reaction?
NISA [10]

A.  This is not a redox reaction. It is an example of combustion.

<h3>Combustion reaction of hydrocarbon</h3>

During the combustion of a hydrocarbon, the hydrocarbon reacts with oxygen to create carbon dioxide, water, and heat.

<h3>Example of combustion reaction</h3>

2C8H18 + 25O2 → 16CO2 + 18H2O

Thus, we can conclude that, this is not a redox reaction. It is an example of combustion.

Learn more about combustion here: brainly.com/question/9425444

#SPJ1

8 0
1 year ago
Papi munyanyo eeeeeeeeeeeeeeeeeeeeeeeeeeee
xenn [34]

Answer:

YES YES YES YES YES YES YES YES YES YES YES YES

8 0
2 years ago
Read 2 more answers
Nevermind, scratch the question
Lyrx [107]
What question there’s no question on here
5 0
1 year ago
PLEASE HELP DUE TODAY 55 POINTS
Dvinal [7]

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

3 0
3 years ago
Read 2 more answers
How many grams of solid nickel will be plated if an aqueous nickel(II) sulfate solution is electroplated over 10.5 min with a co
Anna71 [15]

Answer:

613 mg

Explanation:

$Ni^{2+} + 2e \rightarrow Ni(s)$

Number of fargday's  $=\frac{It}{96500}$

Here, I = 9.20 A

        t = 10.5 min

          = 10.5 x 60 seconds

So, $\frac{It}{96500}$

  $=\frac{3.20 \times 10.5 \times 60}{96500}$

 = 0.0208 F

Here, 2e, 2F

2F = 1 mol of Ni

$0.0208 \ F = \frac{0.0208}{2} = 0.0104 \ mol \ Ni$

1 mol = 59 gm of Ni

0.0104 mol = 59 x0.0104 gm Ni

                    = 0.613 gm Ni

                    = (0.613 x 1000 ) mg of Ni

                    = 613 mg of Ni

3 0
2 years ago
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