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Vera_Pavlovna [14]
2 years ago
13

If a yellow paint is to have 0.511% pbcro4 by mass, how many grams of chromite are needed per kilogram of paint?

Chemistry
1 answer:
Hitman42 [59]2 years ago
5 0

Yellow paint has 0.511 % PbCrO4 by mass

Mass of PbCrO4 in 1 kg of paint = (0.511 / 100) * 1 kg = 0.00511 kg = 5.11 g

Moles of PbCrO4 = 5.11 g/ 323.19 g/mol

                           = 0.0158 moles

Moles of K2CrO4 also = 0.0158 moles

Moles of FeCr2O4 = 0.0158 moles K2CrO4 * (4 mole FeCr2O4 / 8 moles K2CrO4)

                            = 0.0079 moles

Mass of FeCr2O4 (chromite) = 0.0079 moles * 223.83 g/mol

                                            = 1.77 g

Paint is a colored liquid, liquefiable, or solid mastic composition that transforms into a thin solid film after being applied to a substrate. Most commonly used for protection, coloring, or adding texture. Paints come in a variety of colors and can be made in a variety of ways.

Paint consists of pigments, solvents, resins, and various additives. Pigments give the paint its color. Solvents make application easier. The resin helps dry. Additives range from fillers to antifungal agents. There are hundreds of different natural and synthetic pigments.

Learn more about  paint here

brainly.com/question/17996239

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Match each of the following descriptions to thecorrect element listed
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Answer: Please see explanation for answer

Explanation:Matching the  descriptions to the correct element listed gives

Element Group Name Group No Metal/ Nonmetal/ Metalloid Description

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4 0
3 years ago
a laboratory procedure calls for making 510.0 mL of a 1.6 M KNO3 solution. How much KNO3 in grams is needed
barxatty [35]

Answer:

82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.

Explanation:

Since molarity is the number of moles of solute that are dissolved in a given volume, calculated by dividing the moles of solute by the volume of the solution, the following rule of three can be applied: if in 1 L (1,000 mL) of KNO₃ there are 1.6 moles of the compound present, in 510 mL how many moles will there be?

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Being the molar mass of the elements:

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So the molar mass of the compound KNO₃ is:

KNO₃= 39 g/mole + 14 g/mole + 3*16 g/mole= 101 g/mole

Now I can apply the following rule of three: if in 1 mole of KNO₃ there are 101 g, in 0.816 moles how much mass is there?

mass=\frac{0.816 moles*101 grams}{1 mole}

mass= 82.416 grams

<u><em>82.416 g of KNO ₃  is needed to produce 510.0 mL of a 1.6 M KNO ₃ solution.</em></u>

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