Question

I a liter jar contains 0.5 moles of gas at a pressure of 2 ATM what is the temperature of the gas

Answer 1

Answer:

The temperature of the gas is 48.75 Kelvin.

Explanation:

Using the ideal gas equation as shown

PV = nRT where;

P is the pressure of the gas in ATM

V is the volume of the gas

n is the number of moles

R is the ideal gas constant

T is the temperature in Kelvin

From the formula, $T = \frac{PV}{nR}$

Given the following parameters V = 1litre, n = 0.5moles. pressure = 2ATM

R = 0.08206 atm L/molK

On substituting to get the temperature we have:

$T = \frac{2*1}{0.08206*0.5} \\T = \frac{2}{0.04103}\\T = 48.75Kelvin$