Answer:
The magnetic flux through surface is
Wb
Explanation:
Given :
Magnitude of magnetic field
T
Radius of circle
m
Angle between field and surface normal
25°
From the formula of flux,


Where
angle between magnetic field line and surface normal,
area of circular surface.



Magnetic flux is given by,

Wb
Therefore, the magnetic flux through surface is
Wb
It is wasted, most likely as light, in this case, or it is lost during the transport of electricity.
Answer
given,
discharge rate from pipe = 1000 gallons/minutes
now,
flow rate in cubic meters per second
1 gallon = 0.00378541 m³
1 min = 60 s
Q = 
Q = 0.063 m³/s
flow rate in liters per minute
1 gallon = 3.78541 L
Q = 
Q = 3785.41 m³/min
flow rate in cubic feet per second
1 gallon = 0.133681 ft³
1 min = 60 s
Q = 
Q = 2.23 ft³/s
Answer:
0.301 m
Explanation:
Torque = Force × Radius
τ = Fr
40.0 Nm = 133 N × r
r = 0.301 m
The mechanic must apply the force 0.301 m from the nut.