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MakcuM [25]
3 years ago
15

I a liter jar contains 0.5 moles of gas at a pressure of 2 ATM what is the temperature of the gas

Physics
1 answer:
sweet [91]3 years ago
5 0

Answer:

<h2>The temperature of the gas is 48.75 Kelvin.</h2>

Explanation:

Using the ideal gas equation as shown

PV = nRT where;

P is the pressure of the gas in ATM

V is the volume of the gas

n is the number of moles

R is the ideal gas constant

T is the temperature in Kelvin

From the formula, T = \frac{PV}{nR}

Given the following parameters V = 1litre, n = 0.5moles. pressure = 2ATM

R = 0.08206 atm L/molK

On substituting to get the temperature we have:

T = \frac{2*1}{0.08206*0.5} \\T = \frac{2}{0.04103}\\T = 48.75Kelvin

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Answer:

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3 years ago
An airplane travels 4000m in 16 seconds on a heading of 35 whats is its velocity
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6 0
3 years ago
Please answer this question for me and explain why.
horsena [70]

Answer:

D.None of these

Explanation:

The derivation of acceleration formula:

Let us call the 5kg mass m_2 and the 4kg mass m_1. If the tension in the string is T then for the mass m_2

(1). T-m_2g=-m_2a <em>(the negative sign on the right side indicates that acceleration is downwards)</em>

And for the mass m_1

(2). T-m_1g =m_1a<em> (the acceleration is upwards, hence the positive sign)</em>

Solving for T in the 2nd equation we get:

T =m_1a+m_1g,

and putting this into the 1st equation we get:

m_1a+m_1g-m_2g=-m_2a\\\\m_1a+m_2a = m_2g-m_1g\\\\a(m_1+m_2)= (m_2-m_1)g

\boxed{a= \dfrac{(m_2-m_1)}{(m_1+m_2)} g}

Back to the question:

Using the formula for the acceleration we find

a= \dfrac{(5kg-4kg)}{(5kg+4kg)} g

a = \dfrac{g}{9},

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