All categories

3 years ago

What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?

Physics

1 answer:

AlekseyPX3 years ago

3 0

Answer:

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

The time of free fall is given by

t = √2y/g

g = acceleration due to gravity

t = √(2*1.25)/9.8

t = √2.5/9.8

t = 0.5secs

Hang time = 2*0.5

= 1 sec

You might be interested in

A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S

ankoles [38]

Answer is miles sir your welcome it was simple

6 0

3 years ago

A proton travels at a velocity of 3.0x10^6 m/s in a direction perpendicular to a uniform magnetic field.

Virty [35]

Answer:

0.239 T

Explanation:

Applying,

F = Bvqsin∅................ Equation 1

Where F = magnetic force, B = magnetic Field, q = charge of a proton, v = velocity of proton, ∅ = angle between the velocity and the magnetic field.

make B the subject of the equation

B = F/(vqsin∅)................. Equation 2

From the question,

Given: F = 1.15×10⁻¹³ N, v = 3.0×10⁶ m/s, ∅ = 90°(perpendicular)

Constant: q = 1.602 x 10⁻¹⁹ C

Substitute into equation 2

B = 1.15×10⁻¹³ /(3.0×10⁶×1.602 x 10⁻¹⁹×sin90°)

B = 1.15×10⁻¹³/(4.806×10⁻¹³)

B = 0.239 T.

Hence the magnetic field = 0.239 T

7 0

3 years ago

A satellite is launched to orbit the Earth at an altitude of 2.90 x10^7 m for use in the Global Positioning System (GPS). Take t

marin [14]

Answer:

$T=66262.4s$

Explanation:

From the question we are told that:

Altitude $A=2.90 *10^7$

Mass $m=5.97 * 10^{24} kg$

Radius $r=6.38 *10^6 m.$

Generally the equation for Satellite Speed is mathematically given by

$V=(\frac{GM}{d} )^{0.5}$

$V=(\frac{6.67*10^{-11}*5.97 * 10^{24}}{6.38 *10^6+2.90 *10^7} )^{0.5}$

$V=3354.83m/s$

Therefore

Period T is Given as

$T=\frac{2 \pi *a}{V}$

$T=\frac{2 \pi *(6.38 *10^6+2.90 *10^7}{3354.83}$

$T=66262.4s$

4 0

3 years ago

g During the contraction of the heart, 65 cm3 blood is ejected from the left ventricle into the aorta with a velocity of approxi

Alisiya [41]

Answer:

The force is $F = 0.1441 \ N$

Explanation:

From the question we are told that

The volume of blood ejected is $V_b = 65cm^3 = 65*10^{-6} \ m^3$

The velocity of the ejected blood is $v = 98 cm/ s = 0.98 \ m/s$

The mass density of blood is $\rho = 1060 \ kg/m^3$

The heart rate is $R = 61 bpm(beats \ per \ miunite) = \frac{61}{60} = 1.0667\ bps$

Generally the average force exerted is mathematically represented as

$F = 2 * \rho * V_b * R * v$

=> $F = 2 * 1060 * (65*10^{-6}) *1.0667 * 0.98$

=> $F = 0.1441 \ N$

8 0

3 years ago

What is causing the plates of granite rock to flake off

butalik [34]

Earth erosion maybe

6 0

4 years ago

Read 2 more answers