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Sergeeva-Olga [200]
3 years ago
12

What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?

Physics
1 answer:
AlekseyPX3 years ago
3 0

Answer:

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

The time of free fall is given by

t = √2y/g

g = acceleration due to gravity

t = √(2*1.25)/9.8

t = √2.5/9.8

t = 0.5secs

Hang time = 2*0.5

= 1 sec

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Question 2.
choli [55]

Explanation:

1 inch = 25.4 mm

1 foot = 12 inches

1 mile = 5260 feet

1 cm = 0.01 m or 10 mm

Now Sammy's height is 5 feet and 5.3 inches.

(a) We need to find Sammy's height in inches.

Since, 1 foot = 12 inches

5 feet = 5 × 12 inches = 60 inches

Now, 5 feet and 5.3 inches = 60 inches + 5.3 inches = 65.3 inches

Sammy's height is 65.3 inches.

(b) We need to find Sammy's height in feet.

Since, 1 foot = 12 inches

1\ \text{inch}=\dfrac{1}{12}\ \text{feet}

So,

5.3\ \text{inch}=\dfrac{5.3}{12}\ \text{feet}=0.4416\ \text{feet}

5 feet and 5.3 inches = 5 feet + 0.4416 feet = 5.44 feet

Sammy's height is 5.44 feet.

3 0
3 years ago
What are the magnitude and direction of the acceleration of an electron at a point where the electric field has magnitude 6100 n
Hoochie [10]

Force on electron due to electric field is given by

F = eE

F = 1.6 * 10^{-19}* 6100

F = 9.76 * 10^{-16} N

now the acceleration is given by

a = \frac{F}{m}

a = \frac{9.76 * 10^{-16}}{9.1 * 10^{-31}}

a = 1.07 * 10^{15} m/s^2

so above is the magnitude of acceleration and its direction is opposite to field as electron is negatively charged so direction is towards SOUTH

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