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3 years ago

7

How does water get up to the atmosphere, and how does it get back down to earth surface

1 answer:

IrinaK [193]3 years ago

6 0

Answer:

Water gets up to the Earth's atmosphere by evaporating from a body of water, which is then they become water vapor. It returns back to the surface by returning back to its water state and falling back down (as rain). The water vapor turns into clouds (clouds are really just water droplets), and when it cannot hold anymore waters, it disperses all the water (by raining).

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Describe how you would see the apple in the dark.

OLEGan [10]

You will see the apple after your eyes have had time to adjust to the darkness, but you will not see the red color.

8 0

3 years ago

You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that

ra1l [238]

Answer:

a) $I=0.012\ kg.m^2$

b) $I=0.012\ kg.m^2$

Explanation:

Given that:

mass of rod, $m=0.4\ kg$

length of the rod, $l=0.6\ kg$

<u>(a)</u>

<u>Moment of inertia of rod about its center and perpendicular to the rod is given as:</u>

$I=\frac{1}{12} m.l^2$

$I=\frac{1}{12} 0.4\times 0.6^2$

$I=0.012\ kg.m^2$

(b)

<u>Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.</u>

<em>We treat it as two rod with axis of rotation at the end and perpendicular to the plane of rotation. </em>

<em>So, the mass and the length of the rod will become half of initial value.</em>

$I=I_1+I_2$

$I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2$

$I=2[ \frac{1}{3}\times 0.2\times 0.3^2]$

$I=0.012\ kg.m^2$

7 0

3 years ago

How much work<br> was done to<br> accelerate a 2.2<br> kg object from<br> rest to 26m/s?

Makovka662 [10]

Answer:

Explanation:

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>change</em><em> </em><em>in</em><em> </em><em>kinetic</em><em> </em><em>energy</em><em>,</em><em> </em><em>assuming</em><em> </em><em>there</em><em> </em><em>are</em><em> </em><em>no</em><em> </em><em>energy</em><em> </em><em>losses</em><em>.</em>

<em>work</em><em> </em><em>done</em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>m</em><em> </em><em>×</em><em> </em><em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>in</em><em> </em><em>v</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>(</em><em> </em><em>26</em><em>^</em><em>2</em><em> </em><em>-</em><em> </em><em>0</em><em>^</em><em>2</em><em>)</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>1</em><em>/</em><em>2</em><em> </em><em>×</em><em> </em><em>2</em><em>.</em><em>2</em><em> </em><em>×</em><em> </em><em>676</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em> </em><em>743</em><em>.</em><em>6</em><em> </em><em>joules</em>

4 0

2 years ago

What is the difference between accurate data and reproducible data?

vladimir1956 [14]

Accuracy is a general concept while precision is more of a mathematical concept.

4 0

3 years ago

Read 2 more answers

A current-carrying wire 0.50 m long is positioned perpendicular to a uniform magnetic field. If the current is 10.0 A and there

____ [38]

<em>Answer</em>

0.6 teslas

<em>Explanation</em>

When a conductor is inside a magnetic field it experiences a force given by;

Force = ILBsinθ

Where I⇒ current

L ⇒length of the conductor

B ⇒ magnetic field strength

θ ⇒ Angle between the conductor and magnetic field.

F = ILBsinθ

When θ = 90°, Then sin 90 =1 and the formula becomes;

F =ILB

3 = 10 × 0.5 × B

3 = 5B

B = 3/5

= 0.6

magnetic field strength = 0.6 teslas

7 0

3 years ago