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statuscvo [17]
3 years ago
7

How does water get up to the atmosphere, and how does it get back down to earth surface

Physics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

Water gets up to the Earth's atmosphere by evaporating from a body of water, which is then they become water vapor. It returns back to the surface by returning back to its water state and falling back down (as rain). The water vapor turns into clouds (clouds are really just water droplets), and when it cannot hold anymore waters, it disperses all the water (by raining).

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What chemical bond is formed when an equal exchange of electrons occurs?
dangina [55]
I believe it is ionic try it
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4 years ago
22. (I) A car slows down from 28 m/s to rest in a distance of
lidiya [134]

Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

                                          v = d/t

∴                                         t = d/v

Substituting in the above values in the given equation

                                           t = 88/28

                                            = 3.142 s

The acceleration is given by the formula

                                         a = (v-u)/t

                                            = (0 - 28)/3.142

                                            = -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

7 0
4 years ago
How many elements are in CoH1206?
aliina [53]

Answer:

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4 0
4 years ago
Read 2 more answers
 A hotdog cannon shoots a hotdog straight up in the air with an initial velocity of 30 m/s. How high will the hotdog fly?
Yuri [45]

At its peak height, the hotdog will have no vertical velocity, so that

{v_f}^2-{v_i}^2=2(-g)\Delta y\implies-\left(30\,\dfrac{\mathrm m}{\mathrm s}\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}

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7 0
3 years ago
According to​ Newton's Law of​ Cooling, if a body with temperature Upper T 1 is placed in surroundings with temperature Upper T
lesantik [10]

Answer:

27.22 F.

Explanation:

T ( t ) = T₀ + ( T₁ - T₀)e^{-kt}

T ( t ) = 41 ,  T₀ = 0 , T₁ = 140 , t = 15

Put these values in the equation above

41 = ( 140 - 0 ) e^{-15k}

41/140 = e ^{-15k}

(41/140)^{1/3} = e ^{-5k}

Let after 20 minutes temperature becomes T

T = 0 + 140 e^{-k20}

T / 41 = e^{-5k }

= (41/140)^{1/3}

T = 41 X  (41/140)^{1/3}

= 27.22 F.

7 0
4 years ago
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