In reality, the fish are in the ocean.
Answer:
(i) C=3Co
(ii) V=Vo/3
(iii) Decrease
Explanation:
(i) capacitance increase K times.
(ii) As charge remain constant so by using Q=CV
you will get potential decrease by K time.
(iii) Decrease due to induced electric field inside
dielectric material..
E=Eo-Eind
Explanation:
heyaaa hope it helps ☺️✌️
Answer:
<h3>The answer is 336 kgm/s</h3>
Explanation:
The momentum of an object can be found by using the formula
<h3>momentum = mass × velocity</h3>
From the question
mass = 4 kg
velocity = 84 m/s
We have
momentum = 4 × 84
We have the final answer as
<h3>336 kgm/s</h3>
Hope this helps you
<u>Explanation for the given picture:</u>
Initially, three principles of movement proposed by Sir Isaac Newton in 1686 "Principia Mathematica Philosophiae Naturalis". The third law says that every action (force) in nature has an equal but has opposite reaction.
In other words, when object A produces force on object B, then this object B also exerts the same but opposite forces on object A. Remember that forces get exerted on various objects. For example, if we put a wooden block in the floor, this block will create a force that should be equal to its mass, W = mg, which will work down.
The photo above clearly shows a person jumping off a tree on a wooden board, and therefore bouncing on the board because of the force exerted by the wooden board. Newton's third law is important if a person uses his power as weight (W = mg), and this in turn turns the person upside down! hence
Newtons 3rd law applies in above picture.
Answer:
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Explanation:
Total force required = Mass x Acceleration,
F = ma
Here we need to consider the system as combine, total mass need to be considered.
Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg
We need to accelerate the group of rocks from the road at 0.250 m/s²
That is acceleration, a = 0.250 m/s²
Force required, F = ma = 1744 x 0.25 = 436 N
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
