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Tatiana [17]
3 years ago
11

Write a program that calls a function to change a variable value from miles to kilometers.

Computers and Technology
1 answer:
Aneli [31]3 years ago
7 0

Answer:

#include <iostream>

using namespace std;

void miles_to_km(float &miles)//function to convert miles to kilo meters.

{

   miles=miles*1.6;

}

int main() {

   float miles;

   cout<<"Enter the miles"<<endl;

   cin>>miles;//taking input of the miles..

  miles_to_km(miles);//calling function that converts miles to km..

   cout<<"The number of km is "<<miles<<endl;//printing the km.

return 0;

}

Output:-

Enter the miles

54

The number of km is 86.4

Explanation:

I have created  a function miles_to_km of type void which has the argument miles passed by reference.In the function the variable miles is converted to kilo meters.Then in the main function the function is called with the value prompted from the user.Then printing the changed value.

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An alarm clock draws 0.5 A of current when connected to a 120 volt circuit. Calculate its resistance.
mixas84 [53]

Answer:

120 vpm

Explanation:

8 0
3 years ago
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190 rad/s2 until it reaches its final angu
Nataly_w [17]
The first thing we are going to do is find the equation of motion:
 ωf = ωi + αt
 θ = ωi*t + 1/2αt^2
 Where:
 ωf = final angular velocity
 ωi = initial angular velocity
 α = Angular acceleration
 θ = Revolutions.
 t = time.
 We have then:
 ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
 ωi = 0
 α = 190 rad / s2
 Clearing t:
 753.60 = 0 + 190*t
 t = 753.60 / 190
 t = 3.97 s
 Then, replacing the time:
 θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
 θ1 = 1494.51 rad
 For (10-3.97) s:
 θ2 = ωf * t
 θ2 = (753.60 rad / s) * (10-3.97) s
 θ2 = 4544,208 rad
 Number of final revolutions:
 θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
 θ1 + θ2 = 961.57 rev
 Answer:
 the disk has made 961.57 rev 10.0 s after it starts up
3 0
3 years ago
Read 2 more answers
A computing company is running a set of processes every day. Each process has its own start time and finish time, during which i
Helga [31]

Answer:

Above all else, let us show that this issue has the greedy choice property.

This implies that worldwide ideal arrangement can be gotten by choosing local ideal arrangements. Presently notice the following:

The global optimal solution of the issue requests us to track down the minimum number of times process_check module should be run.

It is likewise referenced that during each running interaction, process_check module should be called atleast once. Along these lines, the minimum possible number of process_check calls happens when process_check is made close to the quantity of the processes that are run.

Along these lines, we see that the global optimal solution is shaped by choosing optimal answer for the nearby advances.

Along these lines, the issue shows greedy choice property. Thus, we can utilize a greedy algorithm for this issue.

The greedy step in this calculation is to postpone the process_check as far as might be feasible. Thus, it should be run towards the finish of each interaction. So the following algorithm can be utilized:

Sort the cycles by utilizing the completion times.

Towards the finish of the 1st process in the arranged list, run the process_check module. Right now any process that is now running is removed the arranged rundown. The main interaction is additionally removed from the sorted list.

Now repeat stage 2, till all processes are finished.

In the above mentioned algorithm, the costliest advance is the step of sorting. By utilizing the optimal sorting algorithm, for example, merge sort, we can achieve it in O(n log n) asymptotic time.

Along these lines, this greedy algorithm additionally takes O(n log n) asymptotic time complexity.

5 0
3 years ago
I'm trying to connect fire stick but it doesn't have HDMI input so guys what would do you recommend to buy I tried a converter b
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3 years ago
A government agency is getting rid of older workstations. The agency will donate these workstations, along with other excess com
algol [13]

The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.

<h3>What is a hard disc?</h3>

The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M, and the further discussion can be defined as follows:

The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.

The sparging eliminates statistics to entirely delete the gravitational flux from electronic media.

Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data.

It could no longer be seen as storage after a disk is degaussed.

Therefore, the final answer is "Using the DoD 5220.22-M method and  Degauss media with a magnet".

Learn more about hard disc at:

brainly.com/question/13329582

#SPJ1

3 0
2 years ago
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